1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elden [556K]
3 years ago
5

Is it possible to stop time

Physics
1 answer:
finlep [7]3 years ago
8 0

Answer:

NO

Explanation:

NO ES POSIBLE

You might be interested in
Mount mckinley in Alaska is America’s highest mountain at 20,320 feet. Find it’s height in kilometers. 1mi = 1.609 km= 5280. Ans
Leto [7]

Answer:

I believe the answer is:

6.193536

5 0
3 years ago
In general, what do you think are the benefits if you already achieve your body goals.​
balandron [24]

Answer:

exercise dailyyy

Help you control your weight. ...

Reduce your risk of heart diseases. ...

Help your body manage blood sugar and insulin levels. ...

Help you quit smoking. ...

Improve your mental health and mood. ...

Help keep your thinking, learning, and judgment skills sharp as you age.

Explanation:

7 0
3 years ago
A goal is scored soccer when
wel
A goal is scored soccer when the ball crosses the goal line. That is the basic rule in obtaining points in a soccer game. However, there could be circumstances where the referee has the call to determine whether a point is made.
5 0
3 years ago
Read 2 more answers
In case A below, a 1 kg solid sphere is released from rest at point S. It rolls without slipping down the ramp shown, and is lau
mestny [16]

Answer:

the block reaches higher than the sphere

\frac{y_{sphere}} {y_block} = 5/7

Explanation:

We are going to solve this interesting problem

A) in this case a sphere rolls on the ramp, let's find the speed of the center of mass at the exit of the ramp

Let's use the concept of conservation of energy

starting point. At the top of the ramp

         Em₀ = U = m g y₁

final point. At the exit of the ramp

         Em_f = K + U = ½ m v² + ½ I w² + m g y₂

notice that we include the translational and rotational energy, we assume that the height of the exit ramp is y₂

energy is conserved

          Em₀ = Em_f

         m g y₁ = ½ m v² + ½ I w² + m g y₂

angular and linear velocity are related

        v = w r

the moment of inertia of a sphere is

         I = \frac{2}{5} m r²

we substitute

         m g (y₁ - y₂) = ½ m v² + ½ (\frac{2}{5} m r²) (\frac{v}{r})²

         m g h = ½ m v² (1 + \frac{2}{5})

where h is the difference in height between the two sides of the ramp

h = y₂ -y₁

         mg h = \frac{7}{5} (\frac{1}{2} m v²)

         v = √5/7  √2gh

This is the exit velocity of the vertical movement of the sphere

         v_sphere = 0.845 √2gh

B) is the same case, but for a box without friction

   starting point

          Em₀ = U = mg y₁

   final point

          Em_f = K + U = ½ m v² + m g y₂

          Em₀ = Em_f

          mg y₁ = ½ m v² + m g y₂

          m g (y₁ -y₂) = ½ m v²

          v = √2gh

this is the speed of the box

          v_box = √2gh

to know which body reaches higher in the air we can use the kinematic relations

          v² = v₀² - 2 g y

at the highest point v = 0

           y = vo₀²/ 2g

for the sphere

           y_sphere = 5/7 2gh / 2g

           y_esfera = 5/7 h

for the block

           y_block = 2gh / 2g

            y_block = h

       

therefore the block reaches higher than the sphere

         \frac{y_{sphere}} {y_bolck} = 5/7

3 0
3 years ago
An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.40 kW. A receiving antenna 6
lara [203]

To solve the problem we will apply the concepts related to the Intensity as a function of the power and the area, as well as the electric field as a function of the current, the speed of light and the permeability in free space, as shown below.

The intensity of the wave at the receiver is

I = \frac{P_{avg}}{A}

I = \frac{P_{avg}}{4\pi r^2}

I = \frac{3.4*10^3}{4\pi(4*1609.34)^2} \rightarrow 1mile = 1609.3m

I = 6.529*10^{-6}W/m^2

The amplitude of electric field at the receiver is

I = \frac{E_{max}^2}{2\mu_0 c}

E_{max}= \sqrt{2I\mu_0 c}

The amplitude of induced emf by this signal between the ends of the receiving antenna is

\epsilon_{max} = E_{max} d

\epsilon_{max} = \sqrt{2I \mu_0 cd}

Here,

I = Current

\mu_0 = Permeability at free space

c = Light speed

d = Distance

Replacing,

\epsilon_{max} = \sqrt{2(6.529*10^{-6})(4\pi*10^{-7})(3*10^{8})(60.0*10^{-2})}

\epsilon_{max} = 0.05434V

Thus, the amplitude of induced emf by this signal between the ends of the receiving antenna is 0.0543V

6 0
3 years ago
Other questions:
  • An example of sunlight passing through clouds during sunset results in what is often called the cloud's silver lining. Pastel sh
    6·2 answers
  • When is a body said to be motion (movement )?
    9·1 answer
  • Which of the following technologies would produce the most energy in light waves?
    14·1 answer
  • How long does it take to reach the sun?
    15·1 answer
  • How can you double the frequency of a wave if you have control over both the wavelength and the wave velocity?
    5·2 answers
  • A mass of 4 kg is initially moving in the +x direction and collides inelastically with a mass of 8 kg moving in the -x direction
    13·1 answer
  • Question 3 of 5
    14·1 answer
  • The diagram shows the process used in gene therapy.
    12·2 answers
  • List four methods that can be used to separate mixtures and give an example of each method?
    6·1 answer
  • When was the international space station launched
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!