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ivanzaharov [21]
3 years ago
12

If a planet has an average distance from the sun (semi-major axis of its orbit) of 4 astronomical units, what is the period of i

ts orbit?
Physics
1 answer:
alex41 [277]3 years ago
4 0

Q. 380 If a planet has an average distance from the sun (semi-major axis of its orbit) of 4 astronomical units, what is the period of its orbit?

A. 1 years

B. 4 years

C. 64 years

D. 8 years

Q. 382 If a planet has an average distance from the sun (semi-major axis of its orbit) of 4 astronomical units, what is the period of its orbit?

A. 8 years

B. 1 years

C. 12 years

D. 64 years

Chapter 4; Problems 3, 5 3) If a planet has an average distance from the Sun of 4 AU, what is its orbital period? P2 = 43 = 64 P = 64 = 8 years

In conclusion:

The answer is 8 years

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Explanation:

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The diagram below shows the structural formula and 3D model of the same substance. Which substance is represented by the diagram
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The rectangular coordinates of a point are (5.00, y) and the polar coordinates of
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6 0
2 years ago
In a 400-m relay race the anchorman (the person who runs the last 100 m) for team A can run 100 m in 9.8 s. His rival, the ancho
melisa1 [442]

Answer:

largest lead = 3 m

Explanation:

Basically, this problem is about what is the largest possible distance anchorman for team B can have over the anchorman for team A when the final leg started that anchorman for team A won the race. This show that anchorman for team A must have higher velocity than anchorman for team B to won the race as at the starting of final leg team B runner leads the team A runner.

So, first we need to calculate the velocities of both the anchorman  

given data:

Distance = d = 100 m

Time arrival for A = 9.8 s

Time arrival for B = 10.1 s

Velocity of anchorman A = D / Time arrival for A

=100/ 9.8 = 10.2 m/s

Velocity of anchorman B = D / Time arrival for B

=100/10.1 = 9.9 m/s

As speed of anchorman A is greater than anchorman B. So, anchorman A complete the race first than anchorman B. So, anchorman B covered lower distance than anchorman A. So to calculate the covered distance during time 9.8 s for B runner, we use

d = vt

= 9.9 x 9.8 = 97 m  

So, during the same time interval, anchorman A covered 100 m distance which is greater than anchorman B distance which is 97 m.

largest lead = 100 - 97 = 3 m

So if his lead no more than 3 m anchorman A win the race.

5 0
2 years ago
Which sphere is NOT a part of the cycling of oxygen through Earths systems ?
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