Answer:
a .(b+c) = a.b+a.c
Explanation:
As the three vectors are perpendicular to each other, one of them must lie perpendicular to the plane containing the other two vectors…say a lies perpendicular to the plane of b and c.(b + c )gives another vector which lies in same plane of c and b .
Hi. There would be 39 electrons since in atoms there are the same amount of both protons and electrons. Good luck.
Answer:
9.17 m/s
Explanation:
Impulse = change in momentum
FΔt = mΔv
(166 N) (0.39 s) = (7.06 kg) Δv
Δv = 9.17 m/s
Answer is C, one student has more mass, therefore more inertia.
Decompose the forces acting on the block into components that are parallel and perpendicular to the ramp. (See attached free body diagram. Forces are not drawn to scale)
• The net force in the parallel direction is
∑ <em>F</em> (para) = -<em>mg</em> sin(21°) - <em>f</em> = <em>ma</em>
• The net force in the perpendicular direction is
∑ <em>F</em> (perp) = <em>n</em> - <em>mg</em> cos(21°) = 0
Solving the second equation for <em>n</em> gives
<em>n</em> = <em>mg</em> cos(21°)
<em>n</em> = (0.200 kg) (9.80 m/s²) cos(21°)
<em>n</em> ≈ 1.83 N
Then the magnitude of friction is
<em>f</em> = <em>µn</em>
<em>f</em> = 0.25 (1.83 N)
<em>f</em> ≈ 0.457 N
Solve for the acceleration <em>a</em> :
-<em>mg</em> sin(21°) - <em>f</em> = <em>ma</em>
<em>a</em> = (-0.457N - (0.200 kg) (9.80 m/s²) sin(21°))/(0.200 kg)
<em>a</em> ≈ -5.80 m/s²
so the block is decelerating with magnitude
<em>a</em> = 5.80 m/s²
down the ramp.