1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Phantasy [73]
2 years ago
14

3.

Physics
1 answer:
andrey2020 [161]2 years ago
5 0

Please find attached photograph for your answer.

You might be interested in
Michael is playing with two horseshoe magnets. He is trying to get them to touch, but they will not regardless of how hard he tr
Nesterboy [21]
Since like poles repel, the two horseshoe magnets have like poles facing each other, hence they repel each other and therefore they will not come in contact
8 0
3 years ago
Read 2 more answers
Which of the following depends on an object's displacement not distance from the starting point?
spayn [35]
The answer is A) velocity, because velocity is speed and displacement.
Hope this helps
6 0
4 years ago
A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .if after the collision it moves with a velocity of 2
ch4aika [34]

Answer:

-1.2 kg - m/s

Explanation:

\pink{\frak{Given}}\begin{cases}\textsf{ A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .}\\\textsf{ After the collision it moves with a velocity of 2.0m/s in the opposite direction.}\end{cases}

And we need to find out the change in momentum of the body . Here ,

  • velocity before collision (u) = 10m/s
  • velocity after collision (v) = 2m/s .

We know that momentum is defined as amount of motion contained in a body . Mathematically ,

\sf\longrightarrow momentum (p)= mass(m) * velocity(v)

Therefore change in momentum will be,

\sf\longrightarrow \triangle p = mv - mu

Since the direction of velocity changes after the collision , the velocity will be -2m/s .

\sf\longrightarrow \Delta p = 100g( -2m/s -10m/s) \\

\sf\longrightarrow \Delta p =\dfrac{100}{1000}kg ( -12m/s)  \\

\sf\longrightarrow \Delta p   = 0.1 kg * -12m/s \\

\sf\longrightarrow \boxed{\bf \Delta p = -1.2 \ kg-m/s} \\

7 0
2 years ago
Suppose that, while lying on a beach near the equator of a far-off planet watching the sun set over a calm ocean, you start a st
zubka84 [21]

Answer:

R=3818Km

Explanation:

Take a look at the picture. Point A is when you start the stopwatch. Then you stand, the planet rotates an angle α and you are standing at point B.

Since you travel 2π radians in 24H, the angle can be calculated as:

\alpha =\frac{2*\pi *t}{24H}  t being expressed in hours.

\alpha =\frac{2*\pi *11.9s*1H/3600s}{24H}=0.000865rad

From the triangle formed by A,B and the center of the planet, we know that:

cos(\alpha )=\frac{r}{r+H}  Solving for r, we get:

r=\frac{H*cos(\alpha) }{1-cos(\alpha) } =3818Km

6 0
3 years ago
Which one would it be ?
MA_775_DIABLO [31]

the answer to you question is D.

8 0
3 years ago
Other questions:
  • Question 5 (Multiple Choice Worth 3 points) (02.07 MC) Rachel needs to eat fewer carbohydrates to improve her health. Which of t
    14·1 answer
  • What happens to gravitational potential energy as a roller coaster moves down a hill?
    5·1 answer
  • a screwdriver with a 1-cm shaft and a 4-cm handle is used to tighten a screw. calculate the ideal mechanical advantage.
    7·2 answers
  • How do greenhouse gases such as CO2 and N2O contribute to an increase in Earth’s atmospheric temperature?
    8·2 answers
  • Lava that is very runny probably
    8·1 answer
  • Which of the following is a physical property?
    9·2 answers
  • A woman performs 2000 J of work in order to push a cart full of groceries 50 meters. How much force did she apply to the cart?
    13·1 answer
  • This is for physical science, need help :/
    10·1 answer
  • An object of volume 0.0882 m3 is
    11·1 answer
  • A car initially traveling 7 m/s speeds up uniformly at a rate of 3 m/s2 until it reaches a velocity of 22 m/s. How much time did
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!