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Balance the reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coefficient is "1.

Ilia_Sergeevich [38]

Answer:

2H₂O₂ → 2H₂O + O₂

Explanation:

H₂O₂ → H₂O + O₂

The above equation can be balance as illustrated below:

H₂O₂ → H₂O + O₂

There are 2 atoms of O on the left side and a total of 3 atoms on the right side. It can be balance by putting 2 in front of H₂O₂ and 2 in front of H₂O as shown below:

2H₂O₂ → 2H₂O + O₂

Now, the equation is balanced.

**** check ****

Element >>> Left Side >>> Right Side

H >>>>>>>>> 4 >>>>>>>>> 4

O >>>>>>>>> 4 >>>>>>>>> 4

6 0

3 years ago

What is a cool 1 week or less science fair project for grade 9?

Leno4ka [110]

Make a fizzing volcano with facts and pictures of a volcano

3 0

3 years ago

Read 2 more answers

Lee is in customer service. How can she best support her internal customer, Dan? O al Prioritize other tasks and customers O b)

Thepotemich [5.8K]

Answer:

do i care lol LOOK AT THIS

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7 0

2 years ago

How many miles are in 68 grams of copper 2 hydroxide, Cu (OH)2

BabaBlast [244]

Molar mass Cu(OH)₂ = 97.561 g/mol

1 mol --------- 97.561 g
? mol ---------- 68 g

moles = 68 * 1 / 97.561

moles = 68 / 97.561

= 0.6969 moles

hope this helps!

8 0

3 years ago

A 5.325g sample of methyl benzoate, a compound in perfumes , was found to contain 3.758 g of carbon, 0.316 g of hydrogen, and 1.

Alexxandr [17]

Answer: The empirical and molecular formula of the compound is $C_4H_4O$ and $C_8H_8O_2$ respectively

Explanation:

We are given:

Mass of C = 3.758 g

Mass of H = 0.316 g

Mass of O = 1.251 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{3.758g}{12g/mole}=0.313moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.316g}{1g/mole}=0.316moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.251g}{16g/mole}=0.078moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.078 moles.

For Carbon = $\frac{0.313}{0.078}=4.01\approx 4$

For Hydrogen = $\frac{0.316}{0.078}=4.05\approx 4$

For Oxygen = $\frac{0.078}{0.078}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 4 : 1

The empirical formula for the given compound is $C_4H_4O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 130 g/mol

Mass of empirical formula = 68 g/mol

Putting values in above equation, we get:

$n=\frac{130g/mol}{68g/mol}=1.9\approx 2$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(2\times 4)}H_{(2\times 4)}O_{(2\times 2)}=C_8H_8O_2$

Hence, the empirical and molecular formula of the compound is $C_4H_4O$ and $C_8H_8O_2$ respectively

4 0

3 years ago