Mass to moles
5.2 mol/Ca(no3)2 to mol
5.2 mol/Ca(no3)2 / molar mass
5.2 mol/Ca(no3)2 / 164.1= 0.032 g/Ca(no3)2
Let x be the volume of fluid removed and the volume of pure antifreeze that is added. The concentration of antifreeze in the fluid is 0.3, the concentration in pure antifreeze is 1 and that in the final solution is 0.4 The volume of the final solution is 10.
(10 - x)(0.3) + x = 10(0.4)
0.3 + 0.7x = 0.4
x = 1/7 quarts
The volume that should be drained is 1/7 quarts
Answer:
The correct answer is 0.09 percent.
Explanation:
Based on the given information, the atomic radius is 2 × 10⁻¹⁰ m. Now the atomic volume can be determined by using the formula, 4/3πr³. by putting the values we get,
v = 4/3πr³ = 4/3π(2×10⁻¹⁰ m)³
v = 3.35 × 10⁻²⁹ m³
The no. of atoms present in one mole of xenon is 6.02 × 10²³ atoms. Therefore, the total atomic volume will be,
Va = 6.02 × 10²³ × 3.35 × 10⁻²⁹
Va = 2.02 × 10⁻⁵ m³
The %age of total volume occupied can be determined by dividing the total atomic volume with the volume under STP. Under STP, the volume is 22.4 m³ or 2.24 × 10⁻² m³.
Va/V = 2.02 × 10⁻⁵ m³ / 2.24 × 10⁻² m³
= 9.02 × 10⁻⁴ or 0.09 %
Answer:
Sugar dissolves faster in hot water than it does in cold water because hot water has more energy than cold water. When water is heated, the molecules gain energy and, thus, move faster. As they move faster, they come into contact with the sugar more often, causing it to dissolve faster.
