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Hatshy [7]
3 years ago
9

Determine the empirical formulas for the following compounds:

Chemistry
1 answer:
zysi [14]3 years ago
6 0

<u>Explanation:</u>

Empirical formula is defined as the formula in which atoms in a compound are present in simplest whole number ratios.

For the given options:

  • <u>Option a:</u> Acetic acid

Acetic acid having molecular formula C_2H_4O_2. To write the empirical formula, we divide each subscript by 2.

C_{2/2}H_{4/2}O_{2/2}=CH_2O

Hence, the empirical formula for acetic acid is CH_2O

  • <u>Option b:</u> Citric acid

Citric acid having molecular formula C_6H_8O_7. To write the empirical formula, we divide each subscript by 1.

C_{6/1}H_{8/1}O_{7/1}=C_6H_8O_7

Hence, the empirical formula for citric acid is C_6H_8O_7

  • <u>Option c:</u> Hydrazine

Hydrazine having molecular formula N_2H_4. To write the empirical formula, we divide each subscript by 2.

N_{2/2}H_{4/2}=NH_2

Hence, the empirical formula for hydrazine is NH_2

  • <u>Option d:</u> Nicotine

Nicotine having molecular formula C_{10}H_{14}N_2. To write the empirical formula, we divide each subscript by 2.

C_{10/2}H_{14/2}N_{2/1}=C_5H_7N

Hence, the empirical formula for nicotine is C_5H_7N

  • <u>Option e:</u> Butane

Butane having molecular formula C_{4}H_{10}. To write the empirical formula, we divide each subscript by 2.

C_{4/2}H_{10/2}=C_2H_5

Hence, the empirical formula for butane is C_2H_5

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Part A Transmutation is the process of transforming one element into another through nuclear reactions. What will be the nuclide
S_A_V [24]

<u>Answer:</u> The isotope produced after the transmutation process of Cf-249 and C-12 is _{104}^{257}\textrm{Rf}

<u>Explanation:</u>

Transmutation is defined as the process where one chemical isotope gets converted to another chemical isotope. The number of protons or neutrons in the isotope gets changed.

The chemical equation for the reaction of Californium-249 nucleus with Carbon-12 nucleus follows:

_{98}^{249}\textrm{Cf}+_6^{12}\textrm{C}\rightarrow _{Z}^{A}\textrm{X}+4_0^1\textrm{n}

In a nuclear reaction, the total mass and total atomic number remains the same.

<u>To calculate A:</u>

Total mass on reactant side = total mass on product side

249 + 12 = A + 4

A = 257

<u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

98 + 6 = Z + 0

Z = 104

Hence, the isotope produced after the transmutation process of Cf-249 and C-12 is _{104}^{257}\textrm{Rf}

5 0
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Answer: D: a volcano forming a new island in a chain

Explanation:

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In the reaction between lead(II) nitrate and sodium chloride, what, if any, are the spectator ions
Sonja [21]

Answer:

Explanation:

Spectator ions are ions in a solution/reaction that do not take part in a chemical reaction (hence are called "spectator" ions). <u>They can be identified when they are found both in the reactant and product sides</u>.

The reaction between lead(II) nitrate, Pb(NO₃)₂ and sodium chloride, NaCl is illustrated below

Pb(NO₃)₂ + 2NaCl ⇒ PbCl₂ + 2NaNO₃

According to solubility rules, all the compounds above (with the exception of PbCl₂) are all soluble and would dissociate when involved in a reaction.

Hence, the ionic equation based on the description above will be

Pb²⁺ + 2NO₃⁻ + 2Na⁺ + 2Cl⁻  ⇒  PbCl₂ + 2Na⁺ + 2NO₃⁻

From the above ionic equation, <u>it can be noted that both 2NO₃⁻ and 2Na⁺ are found on both the reactant and product side and are hence the spectator ions.</u>

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3 years ago
Which of these is a chemical property of a substance?
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