Answer: Thus 293 moles of Oxygen gas can be stored in a standard gas cylinder at a temperature of 
and a pressure of 15200 kPa
Explanation:
According to ideal gas equation:
P = pressure of gas = 15200 kPa =150 atm (1kPa=0.0098atm)
V = Volume of gas = 47 L
n = number of moles = ?
R = gas constant =
T =temperature =
Thus 293 moles of Oxygen gas can be stored in a standard gas cylinder at a temperature of and a pressure of 15200 kPa
Answer:
The final temperature of the mixture is 22.3°C
Explanation:
Assuming that the 120 g substance at 80°C is water, final temperature of the mixture can be determined using the formula:
Heat lost = Heat gained
Heat = mc∆T where m is mass, c is specific heat capacity of water, and ∆T is the temperature change =<em> Tfinal - Tinitial</em>.
Let the final temperature be T
Heat lost = 120 × c × (T - 80)
Heat gained = 3000 × c × ( T - 20)
Equating the heat lost and heat gained
120 × c × -(T - 80) = 3000 × c × (T - 20)
9600 - 120T = 3000T - 60000
60000 + 9600 = 3000T + 120T
69600 = 3120T
T = 69600/3120
T = 22.3°C
Therefore, the final temperature of the mixture is 22.3°C
Answer:
Should be A, but also I think there should be an arrow between O2 and 2H2O
There is 213 units i believe hope so
