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astra-53 [7]
2 years ago
11

Balance C12H22011 → C + H2

Chemistry
1 answer:
svlad2 [7]2 years ago
7 0

Answer:

What is this?

Explanation:

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Unsur senyawa CaCO3 adalah
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A 2.00L flask was filled with 4.00 mol of HI at a certain temperature and given sufficient time to react. At equilibrium the con
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Answer:

The equilibrium concentration of I₂ is 0.400 M  and HI is 1.20 M, the Keq will be 0.112.

Explanation:

Based on the given information, the equilibrium reaction will be,  

2HI (g) ⇔ H₂ (g) + I₂ (g)

It is given that 4.00 mol of HI was filled in a flask of 2.00 L, thus, the concentration of HI will be,  

= 4.00 mol/2.00 L

= 2.00 mol/L

Based on the reaction, the initial concentration of 2HI is 2.00, H₂ is 0 and I₂ is O. The change in the concentration of 2HI is -x, H₂ is x and I₂ is x. The equilibrium concentration of 2HI will be 0.200-x, H₂ is x and I₂ is x.  

It is given that at equilibrium, the concentration of H₂ or x is 0.400 M.  

Now the equilibrium concentration of HI will be,  

= 2.00 -2x  

= 2.00 - 2 × 0.400

= 1.20 M

The equilibrium concentration of I₂ will be,  

I₂ = x  

= 0.400 M

The equilibrium constant (Keq) will be,  

Keq = [H₂] [I₂] / [HI]²

= (0.400) (0.400) / (1.20)²

= 0.112

Thus, the Keq of the reaction will be 0.112.  

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3 years ago
Fill in the coefficients that will balance the following reaction: a0Hg(CO3)2 + a1AgCl → a2HgCl4 + a3Ag2CO3
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a_{0}=1 \\  \\  &#10; a_{1}=4 \\  \\ &#10; a_{2}=1 \\  \\ &#10; a_{3}=2 \\  \\

The explanation is shown in the image attached with

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2 years ago
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