some regions of a polypeptide may coil or fold back on themselves. this is called <u>secondary structure</u> , and the coils or folds are held in place by <u>hydrogen bonds</u>
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After translation, primary structure is just the arrangement of amino acids. The interactions between the carbonyl, amino, and side groups of the amino acid polymer backbone inside the chain result in the secondary structure of proteins. These interactions are primarily fueled by hydrogen bonds, which result in the formation of alpha helices and beta sheets, which are the primary features of proteins' secondary structures.
To create a useful three-dimensional structure, tertiary structure requires more interactions within the protein chain. Disulfide bonds between cysteines, hydrophobic contacts, ionic bonding, and dipole-dipole interactions are a few of these interactions. To create a useful, three-dimensional protein structure, several protein chains interact in quaternary structure.
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To learn more about secondary structures:
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Answer:
9.09cm3
Explanation:
The following data were obtained from the question:
Mass of dimethyl sulfoxide = 10g
Density of dimethyl sulfoxide = 1.10gcm−3
Volume of dimethyl sulfoxide =?
The density of a substance is simply the mass substance per unit volume of the substance. It is represented mathematically as:
Density = Mass/volume.
With the above formula, we can obtain the volume of dimethyl sulfoxide as follow:
Density = Mass/volume
1.10gcm−3 = 10g/ volume
Cross multiply to express in linear form
1.10gcm−3 x Volume = 10g
Divide both side by 1.10gcm−3
Volume = 10g / 1.10gcm−3
Volume = 9.09cm3
Therefore, the volume of dimethyl sulfoxide the student should pour out is 9.09cm3
The amount of sample that is left after a certain period of time, given the half-life, h, can be calculated through the equation.
A(t) = A(o) (1/2)^(t/d)
where t is the certain period of time. Substituting the known values,
A(t) = (20 mg)(1/2)^(85.80/14.30)
Solving,
A(t) = 0.3125 mg
Hence, the answer is 0.3125 mg.
<u>Answer:</u> The volume of stock solution needed is 90 mL
<u>Explanation:</u>
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the stock sulfuric acid solution
are the molarity and volume of diluted sulfuric acid solution
We are given:
Putting values in above equation, we get:
Hence, the volume of stock solution needed is 90 mL
