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DENIUS [597]
3 years ago
11

Which of the following will reduce copper? zinc mercury fluorine chlorine

Chemistry
2 answers:
garri49 [273]3 years ago
6 0

<u>Answer:</u> The correct answer is Zinc.

<u>Explanation:</u>

Reactivity is defined as the tendency of an element to loose or gain electrons. Metals which loose electrons easily will be considered as more reactive metal.

The reactivity of elements will be judged on the basis of reactivity series. The elements which lie above in the series are more reactive than the elements which lie below in the series. The metals which lie above in the series will easily reduce the metals which lie below in the series.

Copper is the metal which lie above mercury and below zinc.

Thus, zinc is more reactive metal than copper and hence will easily reduce copper from its reaction.

Hence, the correct answer is Zinc.

laiz [17]3 years ago
4 0
Zinc because the only metals that would be able to reduce copper ions in solution would be hydrogen, lead, tin, nickel, iron, zinc, aluminum, Magnesium, sodium, calcium, potassium, and lithium. and according to your answer choices Zinc is the answer.
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2 years ago
What is the ph of a buffer prepared by adding 0.809 mol of the weak acid ha to 0.608 mol of naa in 2.00 l of solution? The disso
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The pH of the buffer is 6.1236.

Explanation:

The strength of any acid solution can be obtained by determining their pH. Even the buffer solution strength of the weak acid can be determined using pH. As the dissociation constant is given, we can determine the pKa value as the negative log of dissociation constant value.

pKa=-log[H] = - log [ 5.66 * 10^{-7}]\\ \\pka = 7 - log (5.66)=7-0.753=6.247\\\\pka = 6.247

The pH of the buffer can be known as

pH = pK_{a} + log[\frac{[A-]}{[HA]}}]

The concentration of [A^{-}] = Moles of [A]/Total volume = 0.608/2 = 0.304 M\\

Similarly, the concentration of [HA] = \frac{Moles of HA}{Total volume} = \frac{0.809}{2} = 0.404

Then the pH of the buffer will be

pH = 6.247 + log [ 0.304/0.404]

pH = 6.247 + log 0.304 - log 0.404=6.247-0.517+0.3936=6.1236

So, the pH of the buffer is 6.1236.

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