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elena-14-01-66 [18.8K]
2 years ago
8

What is the greatest common factor of 722 and 18?

Mathematics
2 answers:
Art [367]2 years ago
8 0

Answer:

3 hope it helps

Mrac [35]2 years ago
7 0
<h3>Answer:</h3>

2

<h3>Solution:</h3>
  • The greatest common factor, or GCF, of 722 and 18 is 2.
  • Why? Because 722 and 18 are <em>evenly divisible by 2.</em>
  • 722 is not evenly divisible by 3, 6, 9, or 18 (the other factors of 18, except 1, which is a factor of all numbers).
  • Therefore, the GCF is 2.

Hope it helps.

Do comment if you have any query.

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Jake is using a horse trailer to take his horses to his new ranch. 1 Horse= 1,200 lb Trailer= 2,700 lb Jake's truck can tow a ma
Kitty [74]

Answer:

Jack can take only 1 horse on his trailer to be towed by the truck without going over the maximum weight the truck.

Step-by-step explanation:

Given:

Weight of 1 horse = 1,200 lb

Weight of trailer = 2,700 lb

Jacks'truck can tow a maximum of 5000 pounds.

To find the maximum number of horses Jack can take in his trailer without going over the maximum weight his truck can tow.

Solution:

Let the maximum number of horses that Jack can take be = x

Using unitary method to find weight of x horses.

If 1 horse weights = 1,200 lb

Then x horses will weight in lbs = 1,200\times x = 1,200x

Total weight of horses and trailer in lbs = 1200x+2700

Since the maximum weight the truck can tow = 5,000 lb, so the inequality can be given as:

1200x+2700\leq5000

Subtracting both sides by 2700.

1200x+2700-2700\leq5000-2700

1200x\leq2300

Dividing both sides by 1200.

\frac{1200x}{1200}\leq\frac{2300}{1200}

x\leq1.91

From the inequality solution for x, we can conclude that Jack can take only 1 horse on his trailer to be towed by the truck without going over the maximum weight the truck.

3 0
3 years ago
A purse originally cost $45.99. This week, it is on sale for 25% off.
sertanlavr [38]

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Step-by-step explanation:

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Find the linear approximation of the function f(x, y, z) = x2 + y2 + z2 at (4, 4, 7) and use it to approximate the number 4.022
miss Akunina [59]

Answer:

80.66

Step-by-step explanation:

L\left( x \right) = f\left( a \right) + f'\left( a \right)\left( {x - a} \right)

f(x, y, z) = x^2+y^2+z^2

Since we have three variables,

L(x, y,z) = f(a, b,c) + f_x (a, b,c) (x - a) + f_y (a, b,c) (y - b) +f_z(a,b,c)(z-c)

f(4, 4, 7) = 4^2+4^2+7^2=81

f_x (a, b,c)=2x=2*4=8\\f_y (a, b,c)=2y=2*4=8\\ f_z(a,b,c)=2z=2*7=14

Therefore:

L(x, y,z) = 81+ 8(x - 4) + 8 (y - 4) +14(z-7)

Using the above:

f(4.02, 3.99, 6.97) =81+ 8(4.02 - 4) + 8 (3.99 - 4) +14(6.97-7)=80.66.

The approximation of  4.02^2 + 3.99^2 + 6.97^2 is 80.66000.

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Answer:

acute

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