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Sliva [168]
2 years ago
11

Given a special license plate tag consists of 5 characters for a small country. The first

Mathematics
1 answer:
tigry1 [53]2 years ago
7 0

Answer:

D

Step-by-step explanation:

Remark

First characters:  6 choices

Second two characters: 25 * 26

Third set of 2: 10 * 10 = 100

6 * 25 * 26 * 100 = 390000

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I am not too sure what the question asking for

but to evaluate f(x) = 300(1.16) power x = 7.500^20

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Which figure best demonstrates the setup for the box method of finding the area of a triangle
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Hi there! The third option shows us the best setup.

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To be able to fill in this formula, we need to have a base and a height. We can't easily find a triangle with given base and height, so we must look for another option.

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According to a 2018 survey by Bankrate, 20% of adults in the United States save nothing for retirement (CNBC website). Suppose t
nalin [4]

Answer:

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they save nothing for retirement, or they save something. The probability of an adult saving nothing for retirement is independent of any other adult. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% of adults in the United States save nothing for retirement (CNBC website).

This means that p = 0.2

Suppose that sixteen adults in the United States are selected randomly.

This means that n = 16

What is the probability that three or less of the selected adults have saved nothing for retirement?

This is:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{16,0}.(0.2)^{0}.(0.8)^{16} = 0.0281

P(X = 1) = C_{16,1}.(0.2)^{1}.(0.8)^{15} = 0.1126

P(X = 2) = C_{16,2}.(0.2)^{2}.(0.8)^{14} = 0.2111

P(X = 3) = C_{16,3}.(0.2)^{3}.(0.8)^{13} = 0.2463

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0281 + 0.1126 + 0.2111 + 0.2463 = 0.5981

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

4 0
3 years ago
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