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Wewaii [24]
3 years ago
5

What of the following best describe XW

Mathematics
1 answer:
Anastasy [175]3 years ago
6 0

Answer:

angle bisector..... I think

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Remember SOHCAHTOA

Sine- opposite/hypotenuse
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Look at the angle (x) you are trying to figure out and pick which one of these it is.

In your calculator, do the equation first to get a decimal

Then press whichever one you chose on the calculator, so if you got like 0.2 by doing opposite/adjacent for tangent, you would type in 0.2 and then the TAN button

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1. What is the marginal distribution of individuals who are underweight?
Katena32 [7]

Answer:

Step-by-step explanation:

You have to divide the TOTAL underweight which is 130, into the total of individuals which is 1000. 130/1000= 0.13 or 13.0%

Answer C.

I just took this quiz today

4 0
3 years ago
Read 2 more answers
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
A multiple regression model has the form = 5 + 6x + 7w as x increases by 1 unit (holding w constant), y is expected to
Hoochie [10]
As x increases, [y] is expected to increase.
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