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Answer: hello your question has some missing data attached below is the missing data
answer :
∑ Volume variance = $55272
∑ Sales price variance = $41944 ( F )
Step-by-step explanation:
<u>First step </u>: prepare a flexible budget data for the current year using the formulae below
flexible budget = Actual units * Budgeted rate
and
Sales price variance = Actual - Budgeted data
Attached below is the Table showing the evaluation of sales price variance and volume variance
Answer:
Integers ={Positive Natuaral Number +Natural numbers having negative sign behind it+Zero}
={------,-3,-2,-1,0,1,2,3,..........}
→Points marked on the X and Y axis on the Coordinate Plane=Integers only
→Point to be marked on the coordinate plane =(-0.5,2)
→As, points on both X and Y axis are integers only.To mark, -0.5 , mark a line between , 0 and -1,that will be ,-0.5.
→You can mark , any terminating decimal on the number line, which is marked with integers only.
→Terminating decimals are those decimals having in the denominator of a fraction.
So, to plot any terminating Decimal on the coordinate plane, you have to use property of Rational Numbers ,which is, you can find infinite number of terminating Decimal between two terminating Decimal.
→Mark -0.5 between 0 and -1 on the X axis.Similarly, mark integer 2 on the Y axis.Draw a line parallel to Y axis ,passing from (-0.5,0) and line parallel to X axis passing through (0,2).The intersection of these two lines will be required point (-0.5,2).
Answer:
(a) The probability mass function of <em>X</em> is:
(b) The most likely value for <em>X</em> is 1.32.
(c) The probability that at least two of the four selected have earthquake insurance is 0.4015.
Step-by-step explanation:
The random variable <em>X</em> is defined as the number among the four homeowners who have earthquake insurance.
The probability that a homeowner has earthquake insurance is, <em>p</em> = 0.33.
The random sample of homeowners selected is, <em>n</em> = 4.
The event of a homeowner having an earthquake insurance is independent of the other three homeowners.
(a)
All the statements above clearly indicate that the random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 4 and <em>p</em> = 0.33.
The probability mass function of <em>X</em> is:
(b)
The most likely value of a random variable is the expected value.
The expected value of a Binomial random variable is:
Compute the expected value of <em>X</em> as follows:
Thus, the most likely value for <em>X</em> is 1.32.
(c)
Compute the probability that at least two of the four selected have earthquake insurance as follows:
P (X ≥ 2) = 1 - P (X < 2)
= 1 - P (X = 0) - P (X = 1)
Thus, the probability that at least two of the four selected have earthquake insurance is 0.4015.