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2 years ago

A voltage _______ is an increase or decrease in the normal line voltage within the range of 5% to -10%.

Engineering

1 answer:

Ainat [17]2 years ago

7 0

A voltage Fluctuation is an increase or decrease in the normal line voltage within the range of 5% to -10%

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At audio frequencies (below 20kHz), electromagnetic waves have very ____ wavelengths. The wavelength is typically much larger th

netineya [11]

Answer:

broad, transmission or power lines, electrical circuit theory

Explanation:

Electromagnetic waves have quite broad wavelengths for audio frequencies. Normally, the wavelength is larger than any of wires used in circuit. Long transmission or power line might be an exception. If the wavelength is much smaller than length of a wire, the basic principles of electronic circuits apply and the principle of electrical circuits is not needed

For wavelength much smaller than length of wire given, the given elements behave as distributed element, so for this condition Maxwell equation is apply

4 0

3 years ago

A square plate of titanium is 12cm along the top, 12cm on the right side, and 5mm thick. A normal tensile force of 15kN is appli

lukranit [14]

Answer:

For the Top Side

- Strain ε = 0.00021739

- Elongation is 0.00260868 cm

For The Right side

- Strain ε = 0.00021739

-Elongation is 0.00347826 cm

Explanation:

Given the data in the question;

Length of the squared titanium plate = 12 cm by 12 cm = 0.12 m by 0.12 m

Thickness = 5 mm = 0.005 m

Force to the Top F $_t$ = 15 kN = 15000 Newton

Force to the right F $_r$ = 20 kN = 20000 Newton

elastic modulus, E = 115 GPa = 115 × 10⁹ pascal

Now, For the Top Side;

- Strain = σ/E = F $_t$ / AE

we substitute

= 15000 / ( 0.12 × 0.005 × (115 × 10⁹) )

= 15000 / 69000000

Strain ε = 0.00021739

- Elongation

Δl = ε × l

we substitute

Δl = 0.00021739 × 12 cm

Δl = 0.00260868 cm

Hence, Elongation is 0.00260868 cm

For The Right side

- Strain = σ/E = F $_r$ / AE

we substitute

Strain = 20000 / ( 0.12 × 0.005 × (115 × 10⁹) )

= 20000 / 69000000

Strain ε = 0.000289855

- Elongation

Δl = ε × l

we substitute

Δl = 0.000289855× 12 cm

Δl = 0.00347826 cm

Hence, Elongation is 0.00347826 cm

5 0

3 years ago

Question 1 : Replacement [42 Pts] Consider the following page reference string:

MakcuM [25]

Answer:

Optimal

Time 123456789101112

RS. ecbeagdcegda

F0. eeeeeeeee e e a

F1 c c c c c c c c c c c

F2 b b b g g g g g g g

F3 a a d d d d d d

Page fault? * * * * * * *

Total page fault:7

2. LRU

Time 1 2 3 4 5 6 7 8 9 10 11 12

RS e c b e a g d c e g d a

F0 e e e e e e e c c c c a

F1 c c c c g g g g g g g

F2 b b b b d d d d d d

F3 a a a a e e e e

Page fault? Y Y Y N Y Y Y Y Y N N Y Total page fault:9

3. LRU approximation algorithm: Second chance

Time 1 2 3 4 5 6 7 8 9 10 11 12

RS e c b e a g d c e g d a

F0 0,e 0,e 0,e 1,e 1,e 0,e 0,e 0,e 1,e 1,e 1,e 0,e

F1 0,c 0,c 0,c 0,c 0,g 0,g 0,g 0,g 1,g 1,g 0,g

F20,b0,b0,b0,b0,d0,d0,d0,d1,d0,dF30,a0,a0,a0,c0,c0,c0,c0,a

Page fault? YYYNYYYYNNNY

Total page fault: 8

4 0

3 years ago

Read 2 more answers

"Water is flowing in a metal pipe. The pipe OD (outside diameter) is 61 cm. The pipe length is 120 m. The pipe wall thickness is

Katarina [22]

Answer:

Total wight =640.7927 KN

Explanation:

Given that

do= 61 cm

L =120

t= 0.9 cm

That is why inner diameter of the pipe

di= 61 - 2 x 0.9 cm

di=59.2 cm

Water density ,ρ = 1 kg/L = 1000 kg/m³

Weight of the pipe ,wt = 2500 N/m

wt = 2500 x 120 N = 300,000 N

The wight of the water

wt ' = ρ V g

$wt'=1000\times \dfrac{\pi}{4}\times (0.61^2-0.0592^2)\times 9.81\times 120 N$

wt'=340792.47 N

That is why total wight

Total wight = wt + wt'

Total wight =300,000+ 340792.47 N

Total wight =640,792.47 N

Total wight =640.7927 KN

7 0

4 years ago

Container need to be inspected

Sedaia [141]

Answer:

than look inside it

Explanation:

well if you need to inspect something, looking is very important

7 0

2 years ago