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Likurg_2 [28]
3 years ago
14

A hypodermic syringe is used to apply a vaccine. If the plunger is moved forward at the steady rate of 20 mm/s and if vaccine le

aks past the plunger at 0.1 of the volume flowrate out the needle opening, calculate the average velocity of the needle exit flow. The inside diameters of the syringe and the needle are 20 mm and 0.7 mm.
Engineering
1 answer:
svlad2 [7]3 years ago
3 0

Answer:

The average velocity of the needle exit flow is 163.27 m/s

Explanation:

Given;

inside diameter of the syringe, d₁ = 20 mm

inside diameter of the needle, d₂ = 0.7 mm

steady flow rate of the plunger, v = 20 mm/s

Apply continuity equation;

Q_{in} = Q_{out}

Considering 0.1 of the volume flowrate out the needle opening, we will have the following equations.

0.1 *Q_{out \ of \ needle} = Q_{in\ syringe}\\\\0.1(A_2v_2) = A_1v_1\\\\v_2 = \frac{A_1v_1}{0.1A_2}\\\\ v_2 = (\frac{A_1}{A_2} )(\frac{v_1}{0.1})\\\\  v_2 = (\frac{d_1^2}{d_2^2} )(\frac{v_1}{0.1})\\\\ v_2 = (\frac{d_1}{d_2} )^2(\frac{v_1}{0.1})\\\\v_2 =  (\frac{20}{0.7} )^2(\frac{20*10^{-3}}{0.1})\\\\v_2 = 163.27 \ m/s

Therefore, the average velocity of the needle exit flow is 163.27 m/s

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For methyl chloride at 100°C the second and third virial coefficients are: B = −242.5 cm 3 ·mol −1 C = 25,200 cm 6 ·mol −2 Calcu
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a)W=12.62 kJ/mol

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\frac{PV}{RT}=z=1+\frac{B}{V}+\frac{C}{V^2}\\   \\P=RT(1+\frac{B}{V} +\frac{C}{V^2})\frac{1}{V}\\

And  

W=-\int\limits^a_b {RT(1+\frac{B}{V} +\frac{C}{V^2}\frac{1}{V}  } \, dV

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After performing integration we get work done on the system is  

W=12.62 kJ/mol

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         dV=RT(-1/p^2+0+C')dP

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W=-\int\limits^a_b {P(RT(-1/p^2+0+C')} \, dP

a=v_2\\

b=v_1

by substituting given limit and P = 1 bar , P2 = 50 bar and T = 373 K we get work  

W=12.59 kJ/mol

The work by differ between a and b because the conversion of constant of virial coefficients are valid only for infinite series  

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