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NeX [460]
3 years ago
15

An R-134a refrigeration system is operating with an evaporator pressure of 200 kPa. The refrigerant is 10% in vapor phase at the

inlet of the evaporator. The enthalpy and temperature of the refrigerant at the exit of the compressor are 360 kJ/kg and 70 /C respectively. If this system (with the refrigerant flowing at 0.005 kg/s) is used to cool a 750 kg product (initial temperature = 80 /C and specific heat = 3,000 J/kg-K), what will be the temperature of the product after 6 hours?

Engineering
1 answer:
crimeas [40]3 years ago
8 0

Answer:

71.17°C

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

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Explanation:

Solution

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y = 1.4

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ΔW = mR ( (T₂ - T₁) / k- 1

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