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LekaFEV [45]
4 years ago
7

In order to produce a certain semiconductor, a process called doping is performed in which phosphorus is diffused into germanium

. If = 2.010 and the activation energy is 240.6 , determine the diffusivity of in at 830. The gas constant is = 8.314. (Express your answer to three significant figures.)
Engineering
1 answer:
Nimfa-mama [501]4 years ago
4 0

Answer:

The diffusivity is given as 8.064\times 10^{-16} m^2/s

Explanation:

From the given data as in the attached question found via the search (because the values were not clear in this one)

D_o=2.0\times10^{-4}m^2/s\\Q_d=240.6 kJ/mol=2.406 \times 10^5 J/mol\\Gas Constant=R=8.314 J/mol K\\Temperature =830 C =830+273 =1103 K

So  the Diffusion coefficient is given as

D=D_oe^{\frac{-Q_d}{RT}}\\D=(2.0\times 10^{-4})e^{\frac{-2.406\times 10^5}{8.314\times 1103}}\\D=8.0640\times 10^{-16} m^2/s

So the diffusivity is given as 8.064\times 10^{-16} m^2/s

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