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2 years ago

Which is the best estimate of the measure of this angle?

Mathematics

1 answer:

Pani-rosa [81]2 years ago

5 0

Answer:

That angle looks like a reflex angle

Step-by-step explanation:

I think D is the answer, since Reflex angles are ALWAYS be more than 180 and less than 360

I hope this helps! So srry if its wrong

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Twenty men can cut thirty trees in four hours. If four men leave the job, how many

Mice21 [21]

Answer:

As in 4 hours , 20 men can cut 30 trees. So, in 1 hour , 20 men can cut 30 trees / 4. So, in 6 hours, 20 men can cut 30 * 6 trees / 4 = 45 trees.

Step-by-step explanation:

done

8 0

3 years ago

Mariah spent $9.50 on 9 pounds of limes and pears. Limes cost $0.50 per pound and pears cost $1.50 per pound. Let l be the numbe

Mashcka [7]

Answer:

4 pounds of lime and 5 pounds of pears

Step-by-step explanation:

I + P = 9

0.5l + 1.5P = 9.5

I = 9 - P

0.5(9 - P) + 1.5P = 9.5

4.5-0.5P + 1.5P = 9.5

4.5 + P (1P) = 9.5

P = 9.5-4.5 = 5

I = 9 - 5 = 4

Answer: 4 pounds of lime and 5 pounds of pears

5 0

3 years ago

What is the answer for -5x-8=3x+10

SIZIF [17.4K]

Answer:

x=− 9 /4

=−2.250

Step-by-step explanation:

4 0

3 years ago

I will give brainliest

Natasha_Volkova [10]

Answer:

225°
quadrant 3
reference angle of 45°

Step-by-step explanation:

585-360= 225

225° is in quad 3

reference angle for quad 3 is

225° - 180°

3 0

3 years ago

Read 2 more answers

A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.

irakobra [83]

Answer:

The integral is equal to $5\sec^2(2x)+C$ for an arbitrary constant C.

Step-by-step explanation:

a) If $u=\tan(2x)$ then $du=2\sec^2(2x)dx$ so the integral becomes $\int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C$ . (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case $u=\sec(2x)$ hence $du=2\tan(2x)\sec(2x)dx$ . We rewrite the integral as $\int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C$ .

c) We use the trigonometric identity $\tan(2x)^2+1=\sec(2x)^2$ is part b). The value of the integral is $5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C$ . which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.

3 0

3 years ago