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Evgesh-ka [11]
3 years ago
8

There is an integer n such that 2n2 − 5n + 2 is prime. To prove the statement it suffices to find a value of n such that (n, 2n2

− 5n + 2) satisfies the property "2n2 − 5n + 2 is prime." Show that you can do this by entering appropriate values for n and 2n2 − 5n + 2.
Mathematics
1 answer:
fomenos3 years ago
7 0

Answer:

n = 0 or 3

Step-by-step explanation:

2n² - 5n + 2

2n² - 4n - n + 2

2n(n - 2) -1(n - 2)

(n - 2)(2n - 1)

Prime number is one which is divisible by itself and 1

n-2 = 1 n = 3

2n-1 = 1 n = 0

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A spinner with 10 equally sized slices is shown below. (3 slices are blue, 2 are yellow, and 5 are rec the probability that the
Ainat [17]

Answer:

1/2

Step-by-step explanation:

Blue + yellow = 3 + 2   = 5     out of 10 slices

     5 out of 10   = 5/10 = 1/2

5 0
2 years ago
What is the value of a and b
TEA [102]
Hey i would answer but you didn’t provide enough context! make sure to upload images with your question hun.
4 0
3 years ago
What is 3.57 as a fraction
Ainat [17]
357/100
because .57 is the same as 57 hundriths which translates to 57/100. Now you have 3 and 57/100 and to make thing into an improper fraction you follow these steps.
1. mulitply the whole number (the number in front on the fraction) by the denominator (the lower part of the fraction). In our case, multiply 3 and 100. You get 300.
2. Add your answer to the numorator (the upper part on the fraction). 300 plus 57 equals 357.
3. Use your answer as the new numorator and keep the original denomanator.
Answer: 357/100
3 0
2 years ago
P1=(-1,3) and P2=(5,-1) <br><br> Find the distance from p1 to P2
LenaWriter [7]

Answer:

7.21

Step-by-step explanation:

Given that:

P1=(-1,3) and P2=(5,-1)

Distance between two points :

d = Sqrt[(x2 - x1)² + (y2 - y1)²]

x1 = - 1 ; y1 = 3

x2 = 5 ; y2 = - 1

d = Sqrt[(5 - (-1))² + ((-1) - 3)²]

d = Sqrt[(5 + 1)² + (-1 - 3)²]

d = sqrt[(6)^2 + (-4)^2]

d = sqrt(36 + 16)

d = sqrt(52)

d = 7.21

3 0
2 years ago
0 Example: Loan payments of $400 due 95 days ago and $700 due today
guapka [62]

Answer:

X=\$519.48

Step-by-step explanation:

From the question we are told that

Loan 1 X_1=\$400

Loan 1 due t_1=95days

Loan 2 X_2=\$700

Loan 2 duet_2=0days

Payment Y=\$600

Worth of money w=6\%

Payment due t=30days

Focal date t_f=125days

Generally \$400 was due 95days ago

Therefore

125+90=220days(total days to consider)

Therefore

300+400 =700 is due today

125days left

Given

600 due in 30days

125-30=95days

Generally the Final payment is mathematically given by

400(1+ 0.06*\frac{220}{365} ) + 700(1+0.06*\frac{125}{365} )=600(1+0.06*\frac{95}{365} )+X

X=1128.9692 - 609.3698

Therefore the

X=\$519.48

3 0
2 years ago
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