Answer: In an experiment, mice were fed glucose (C6H12O6) containing a small amount of radioactive carbon. The mice were closely monitored, and in a few minutes, radioactive carbon atoms showed up in _Carbon dioxide/Carbon IV oxide (CO2)_
Explanation: The end product of Glucose at the end of metabolism is Carbon dioxide, water and ATP.
C6H12O6 + 6O2 ----------> 6CO2 + 6H2O + ATP (Energy)
The carbon is converted to Carbon dioxide. So, the radioactive Carbon appears in the Carbon dioxide/Carbon IV oxide (CO2).
I think the correct answer from the choices listed above is option 2. When the products of a reaction are hotter than the reactants the reaction is endothermic. The change in temperature is a measure of energy difference of the states. Since energy must be conserved, so there must be a source of energy for the system.
Answer:
A I believe this is the answer I do not know look at the picture I attached
Use the h-h equation!
pH = pKa + log[In-/HIn]
2.0 = 9.7 + log[In-/HIn]
-7.7 = log[In-/HIn]
10^-7.7 = [In-/HIn]
[In-/HIn] = 1.995 x 10^-8
Hope this helps!