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Alla [95]
3 years ago
15

Complete and balance each of the following equations. If no reaction occurs, write noreaction:

Chemistry
1 answer:
8090 [49]3 years ago
3 0

Barium chloride reacts with silver nitrate to form  a precipitate of silver chloride along with soluble solution of barium nitrate. The equation is as follows:

BaCl2(aq) + AgNO3(aq) → AgCl(s) + Ba(NO3)2(aq)

Lets balance the equation:

Reactants                                                    Products

# Ba atoms = 1                                       #Ba atoms = 1

# Cl atoms = 2                                       # Cl atoms = 1  

# Ag atoms = 1                                      # Ag atoms = 1

# NO3- group = 1                                  # NO3- group = 2

Thus the balanced equation needs to be balanced w.r.t Cl and NO3-

BaCl2(aq) + 2AgNO3(aq) → 2AgCl(s) + Ba(NO3)2(aq)

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3 years ago
One of relatively few reactions that takes place directly between two solids at room temperature is In this equation, the in Ba(
yuradex [85]

Answer:

3.14 grams of ammonium thiocyanate must be used to react completely with 6.5 g barium hydroxide octahydrate.

Explanation:

Ba(OH)_2.8H_2O(s)+NH_4SCN(s)\rightarrow Ba(SCN)_2(s)+8H_2O(l)+NH_3(g)

The balance chemical equation is :

Ba(OH)_2.8H_2O(s)+2NH_4SCN(s)\rightarrow Ba(SCN)_2(s)+10H_2O(l)+2NH_3(g)

Mass of barium hydroxide octahydrate = 6.5 g

Moles of  barium hydroxide octahydrate = \frac{6.5 g}{315 g/mol}=0.020635 mol

According to reaction, 2 moles of ammonium thiocyanate reacts with1 mole of  barium hydroxide octahydrate. The 0.020635 moles of barium hydroxide octahydrate will react with:

\frac{2}{1}\times 0.020635 mol=0.04127 mol

Mass of 0.04127 moles of ammonium thiocyanate;

0.04127 mol\times 76 g/mol=3.136 g\approx 3.14 g

3.14 grams of ammonium thiocyanate must be used to react completely with 6.5 g barium hydroxide octahydrate

3 0
3 years ago
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