Answer:
So, sodium oxide + water = sodium hydroxide + hydrogen is written Na2O+H2O-->NaOH+H.
To balance the equation it should read NaO+H2O-->2NaOH
Explanation:
Na2O+H2O-->2NaOH+0H2.......the 0H2 is dropped because there is no value
Answer:
If a standard iodine solution is used as a titrant for an oxidizable analyte, the technique is iodimetry. If an excess of iodide is used to reduce a chemical species while simultaneously forming iodine.
<h3>
Answer:</h3>
#1. Type of reaction: Single displacement
#2. Balanced equation: Zn + 2HCI → ZnCI₂ + H₂
<h3>
Explanation:</h3>
<u>We are given;</u>
- The equation; Zn+HCI → ZnCI₂ + H₂
Assuming we are required to identify the type of reaction and balance it;
- The reaction is a <u>single displacement reaction.</u>
- Zinc metal displaces hydrogen atom from hydrochloric acid to form a salt, zinc chloride and hydrogen gas.
- To balance the equation, we put coefficients on the reactants and products for the number of atoms of each element to be equal on both sides of the equation.
- In this case, the appropriate coefficients are 1, 2, 1 and 1
- Therefore, the balanced equation will be;
Zn + 2HCI → ZnCI₂ + H₂
Hi!
<u>HCl is the limiting reactant.</u>
From the equation, we understand that 1 mole of Mg(OH)2 will react with 2 moles of HCl for the reaction to be complete. To find the limiting reactant we need to see which molecule is in lower quantity (in terms of moles and not mass)
Calculating the number of moles of Mg(OH)2 given
Using the formula, number of moles= mass / molecular mass
number of moles = 50.6 / 58 = ~ 0.872
Calculating the number of moles of HCl given
Number of moles = 45 / 36.5 = ~ 1.232
There are several ways to use this information to calculate the limiting reactant. In our case, we can subtract the number of moles of Mg(OH)2 from the number of moles of HCl and check for the remainder.
If it is more than 0.872, then HCl would be in excess, with Mg(OH)2 being the limiting reactant; however, if the remainder is less than 0.872, it would mean <em>HCl is the limiting reactant.</em>
1.232- 0.872 = 0.36
As 0.36 < 0.872 , we see that HCl is the limiting reagent.
NOTE: this is in the case that the moles of HCl needed to complete the reaction is twice that of Mg(OH)2.
Hope this helps!
