I think the answer is yes
1) concentration or partial pressure of species
involved. 2) temperature • 3) presence of catalyst
4) nature of reactants.
If the dehydration reaction of an alcohol is successful. The changes would be seen in the IR spectrum for the product compared to the starting material are as,
- The O-H and C-O band is disappear from stating material
- The addition of a C-C double bond band in the product.
In dehydration reaction of alcohol ( O-H and C-O bond ) contain , the water molecule (
) is release from the reactant and C-C double bond is form which is known as alkene in the product .
The reactant and product have different structure. To determine the structure of the compound IR spectroscopy is used. In IR spectrum the peak corresponds to 3400-3600 cm is missing in the product of dehydration reaction of an alcohol. It means O-H band is disappear from stating material.
learn about IR SPECTRUM
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Answer:
6.25 mL
Explanation:
1.25% of 500 mL is ...
0.0125×(500 mL) = 6.25 mL
Since 1.25% of the 500 mL of solution is bleach, that's how much you need. That amount is 6.25 mL.
Answer:
The different structures are shown in the attachment.
I and II - structural isomers
I and III - Structural isomers
I and IV - structural isomers
II and III - structural isomers
II and IV - structural isomers
III and IV - stereoisomers
Explanation:
The knowledge of Isomerism is tested here; there are two types of isomerism ; structural and stereoisomerism.
- Structural Isomers have similar molecular and different double bond positioning, these occurs mostly in ALKENE FAMILY.
- Stereo-isomers have the same molecular formular and similar patterns but differ in their spatial arrangement. trans and cis are typical examples of stereo-isomers.
From the question; Relationship between I and II is that they are structural isomers since they have the same molecular formula, but different bond atom arrangement and infact they are the same compound.
- Relationship between I and III is that they are structural isomers with similar molecular formular but differ in the double bond position.
- Relationship between I and IV is that they are structural isomers with similar molecular formula but different double bond arrangement.
- Relationship between II and III is that they are structural isomers with similar molecular formular but different double bond position
- Relationship between II and IV is that they are also structural isomers with the same molecular formular but different double bond position.
- Relationship between III and IV is that they are stereo-isomers with same molecular formula but different spatial arrangement, hence cis and trans.