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jok3333 [9.3K]
2 years ago
6

Increasing the concentration of a reactant shifts the position of chemical equilibrium towards formation of more products. What

effect does adding a reactant have on the rates of the forward and reverse reactions?.
Chemistry
1 answer:
lakkis [162]2 years ago
4 0

Answer:

A.There is no effect on the forward and reverse reactions. For an equilibrium reaction, the forward and reverse rates are always equal.

B. Both the forward and reverse reactions speed up by the same amount.

C. The forward reaction speeds up immediately. As more product is made, the reverse reaction starts to speed up as the forward reaction starts to slow down until they are equal.

D. The forward reaction slows down initially. As the reaction proceeds, the reverse reaction slows down to meet the new forward reaction.

E. The forward reaction speeds up. Eventually, production of the product speeds up the reverse reaction rate to match the new forward rate.

F. It is impossible to say without more specific information.

Explanation:

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423.3 mL of gas is at 49.2 C. It is compressed to a volume of 79 mL. What is the new temperture. Express your answer in Kelvin.
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Answer: 60.1K

Explanation:

Initial volume of gas V1 = 423.3mL

Initial temperature T1 = 49.2°C

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Final temperature T2 = ?

Final volume V2 = 79mL

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Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

423.3mL/322.2 = 79mL/T2

To get the value of T2, cross multiply

423.3mL x T2 = 322.2K x 79mL

423.3mL x T2 = 25453.8

T2 = (25453.8/423.3mL)

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3 years ago
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Explanation:

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