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MatroZZZ [7]
3 years ago
5

How many molecules are in the substance formula of 2C6H1206 (use coefficients)

Chemistry
1 answer:
FrozenT [24]3 years ago
6 0

<u>Answer:</u> The number of formula units present in 2 moles of C_6H_{12}O_6 are 1.2044\times 10^{24}

<u>Explanation:</u>

Formula units are defined as the number of molecules or atoms present in 1 mole of a compound or element respectively.

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of formula units

Here, 2 represents the number of moles of C_6H_{12}O_6

We are given:

Moles of C_6H_{12}O_6 (glucose) = 2 moles

Number of formula units of C_6H_{12}O_6=(2\times 6.022\times 10^{23})=1.2044\times 10^{24}

Hence, the number of formula units present in 2 moles of C_6H_{12}O_6 are 1.2044\times 10^{24}

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A ground water tank has its height 2m. Calculate the pressure at its bottom when it is completely filled with water.​
Law Incorporation [45]

The pressure at the bottom : 19600 N/m²

<h3>Further explanation</h3>

Given

A ground water tank has its height 2m

Required

The pressure at its bottom

Solution

Hydrostatic pressure is the pressure caused by the weight of a liquid.  

The weight of a liquid is affected by the force of gravity.  

The hydrostatic pressure of a liquid can be formulated:  

\large{\boxed{\bold {P_h ~ = ~ \rho.g.h}}

Ph = hydrostatic pressure (N / m², Pa)  

ρ = density of liquid (kg / m³)  

g = acceleration due to gravity (m / s²)  

h = height / depth of liquid surface (m)  

ρ = density of water (kg / m³) = 1000

g = acceleration due to gravity = 9.8 m/ sec²

The pressure

\tt P=1000\times 9.8\times 2=19600~N/m^2

6 0
3 years ago
How many grams of NaCl are needed to prepare 1.20 liters of a 2.00 M solution?
larisa86 [58]

Answer: D) 140g

Explanation: no. of moles of NaCl = molarity X volume in litres = 2 X 1.2 = 2.4, and molar mass or mass of 1 mole of NaCl = 58.44 g, so 2.4 moles NaCl = 140.256 g

3 0
3 years ago
What law of motion does this picture represent
alukav5142 [94]

Answer: none

Explanation: there is no picture attached

7 0
3 years ago
Check this if it’s right
FromTheMoon [43]

Answer: yes its right

Explanation:

3 0
4 years ago
A quantity of gas occupies a volume of 804 mL at a temperature of 27 °C. At what temperature will the
irga5000 [103]

Answer:

T₂ = 150 K

Explanation:

Given data:

Initial volume of gas = 804 mL

Initial temperature = 27°C (27+273=300 K)

Final temperature = ?

Final volume = 402 mL

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁/V₁  

T₂ = 402 mL × 300 K / 804 mL

T₂ = 120,600 mL.K / 804 mL

T₂ = 150 K

3 0
3 years ago
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