The correct answer would be 0.1505 M/s. Given the rate of disapperance of HBr, we can easily calculate the rate of apearance of the products by looking at the coefficients of the substances in the reaction. In this case, for every two moles of HBr, 1 mole of Br2 is being produced so the reaction rate would be:
- 1/2 (r(HBr)) = rBr2
- 1/2 (-0.301) = rBr2
Rate of appearance of Br2 = 0.1505 M/s
They both have two electron shells
<h3>Further explanation</h3>
The period 2 element lies in the second row of the periodic system.
Consists of the elements: lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine, and neon
atomic number : 3
electron configuration : [He] 2s¹
atomic number = number of proton=number of electron(in neutral atom)
So Li have 3 protons and 3 electrons
Because it fills the 2s orbital it has 2 shells
atomic number : 8
electron configuration : [He] 2s²2p⁴
So O have 8 protons and 8 electrons
Because it fills the 2s and 2p orbital it has 2 shells
So Lithium (Li) and Oxygen (O) are both have two electron shells
I believe the answer is carbon dioxide
Answer:
There are five signs of a chemical change:
Colour Change.
Production of an odour.
Change of Temperature.
Evolution of a gas (formation of bubbles)
Precipitate (formation of a solid).
