Question: The question is incomplete. Below is the complete question and the answer;
While ethanol (CH3CH2OH is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by reacting ethylene CH2CH2) with water vapor at elevated temperatures. A chemical engineer studying this reaction fills a 50.0 L tank at 22. °C with 24. mol of ethylene gas and 24. mol of water vapor. He then raises the temperature considerably, and when the mixture has come to equilibrium determines that it contains 15.4 mol of ethylene gas and 15.4 mol of water vapor The engineer then adds another 12. mol of water, and allows the mixture to come to equilibrium again. Calculate the moles of ethanol after equilibrium is reached the second time. Round your answer to 2 significant digits.
Answer:
Number of moles of ethanol = 11 mol
Explanation:
SEE THE ATTACHED FILE FOR THE CALCULATION
Answer:The top of the fractional distillation column will have a more volatile liquid as compared to the liquid at the bottom.
Explanation:
Fractional distillation is the method of separating liquids with different boiling points.For example,ethanol can be separated from water from a ethanol-water mixture.The component with a lower boiling point will pass in the column and collected first followed by higher boiling point component.Repeated vaporization and condensation results in the separation of the components in the mixture.
High iron and magnesium rocks have a high percentage of dark-colored (mafic) minerals.
So the high iron and magnesium would be darker than the low iron and magnesium.
46 gram of ethanol ≡ 1 mole of ethanol
1 gram of ethanol ≡ 1/46 mole of ethanol
10 gram of ethanol ≡ 1*10/46 mole of ethanol
=0.217 mole of ethanol
I would believe the answer to this question is D. According to the concept of the tragedy of the commons, shared resources are used by more than one organism. Due to the large consumption of shared resources they start to be fewer and fewer in number and over time if we are not careful they will be depleted.