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Wittaler [7]
3 years ago
5

Helppppppppppppppppp

Chemistry
1 answer:
ExtremeBDS [4]3 years ago
6 0

Answer:

d

Explanation:

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What is ksp for agi, if its molar solubility is 9.1 × 10−9 mol/l?
LekaFEV [45]
When the salt AgI dissolves, it dissociates as follows;
AgI --> Ag⁺ + I⁻
molar solubility of salt is the amount of salt that can be dissolved in 1 L of solution
since the ions dissociated are in 1:1 molar ratio, the molar solubility of the ions are equivalent to the molar solubility of the salt.
ksp is the solubility product constant of the salt
ksp = [Ag⁺][I⁻]
ksp = (9.1 x 10⁻⁹ mol/L)²
ksp = 8.28 x 10⁻¹⁷
4 0
3 years ago
2
stiks02 [169]

Answer:

An organ is a part of the body that carries out its main function. Most organs are made out of tissues.

Explanation:

6 0
3 years ago
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What is the pH of a solution if [H+] = 1.0 x 10-5M? *
marissa [1.9K]

Answer:

5.00

Explanation:

because ignoring the pH solution part and doing the math it comes around to 1.0x5.0 which 1 times anything is itself so its 5

4 0
3 years ago
Ethyne gas combusts with oxygen gas according to the following reaction: Calculate the volume, in mL of CO2 produced when 73 g o
Bezzdna [24]

Answer: Volume of CO2 is 89127 mL

Explanation: The reaction that takes place is: C2H2 + O2 --> CO2 + H2O

The amount of C2H2 that react allow us to predict the amount of CO2 that will be obtained

mol CO2 = 73gC2H2 .\frac{1 mol C2H2}{26gC2H2} . \frac{2mol CO2}{4mol C2H2} = 5,6 mol CO2

26g/1mol is molar mass of C2H2 and 2/4 is the molar relation between CO2 and C2H2 in this reaction. Canceling units, at the end mol of CO2 are obtained

Now with the moles of CO2 and the ideal gases equation is possible to calculate the volumen occupied by the gas.

PV = RnT where P: pressure, V: volume, R: ideal gas constant, n: moles and T: temperature expressed in K (add 273,15 to °C temperature: 37,4°C + 273,15 = 310,55K)

V= RnT/P

V= \frac{0,08206 atmL/molK . 5,6 mol. 310,55 K}{1,6 atm}  =89,127 L

To express volume in mL multiply the L result by 1000 which equals 89127 mL

5 0
3 years ago
When the pressure is 1.22 atm, a sample of hydrogen gas has a volume of 1.88L. What is its volume if the pressure is increased t
Evgesh-ka [11]

Answer:

1.58 L

Explanation:

Use Boyle's law, which is defined as

p1v1 = p2v2

In this case we're solving for V2 because the rest of the variables are given.

p1 = 1.22 atm

v1 = 1.88L

p2 = 1.45 atm

v2 = ?

p1v1 = p2v2

(1.22 atm)(1.88L) = (1.45 atm)(v2)

v2 = (1.22 atm)(1.88L) ÷ (1.45 atm) = 1.58 L

6 0
3 years ago
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