1 answer:
Heat required to raise the temperature = 159.505 J
<h3>Further explanation</h3>
Given
c = specific heat of Beryllium = 1.825 J/g C
m = mass = 2.3 g
Δt = Temperature difference : 60 - 22 = 38 °C
Required
Heat required
Solution
Heat can be formulated
Q = m.c.Δt
Input the value :
Q = 2.3 x 1.825 x 38
Q = 159.505 J
You might be interested in
Answer:
6
Explanation:
You will see H6 and the H stands for helium and the 6 is how many of that atom is there
Density = mass/volume
substituting the given values :
We get :
D = 37.4 / 2.2 x 10^3
D = 0.017 grams/liter
Answer:
41
Explanation:
w = mg
m = w/g
m = 410/10
= 41
The correct answer is D) Malleability
Answer:
V2 = 894.4mL
Explanation:
P1= 124.1, V1= 578mL, P2 = 80.2kPa, V2= ?
Applying Boyle's law
P1V1 = P2V2
Substitute and simplify
124.1*578=80.2*V2
V2= 894.4mL