Use a sheet of paper to propose syntheses of the following alcohols from starting materials containing no more than four carbon
atoms. Take a picture of your answers and post it for others in your group to see. Comment on the posts of at least two other students - have they correctly proposed routes to the four products and do their starting materials contain no more than four carbon atoms
1 answer:
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Answer:
26.110 grams of O2 produced.
Explanation:
Calculate the amount of moles in KClO3 by dividing the amount of grams given by the atomic weight of the substance.
To get the atomic weight: K = 39.098, Cl = 35.45, O = 15.999, and there are 3 molecules of Oxygen, so multiply 15.999 by three.
39.098 + 35.45 + (15.999 * 3) = 122.548.
66.7g / 122.548 atomic mass = 0.544 moles.
The ratio of moles of KClO3 to moles of O2 is 2 to 3.
=
Cross multiply to get 1.632 = 2y. Y = 0.816, meaning 0.816 moles of O2 will be produced.
Convert this into grams by multiplying by the atomic weight of O2 (15.999 * 2 = 31.998).
0.816 * 31.998 = 26.110 grams of O2 produced.