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2 years ago

Radiation, Chemical agents and Viruses.

Chemistry

2 answers:

zmey [24]2 years ago

7 0

Radiation, Chemical agents and viruses may all cause C. Generic Mutations.

klasskru [66]2 years ago

5 0

I think the correct answer from the choices listed above is option C. Radiation, Chemical agents and Viruses may cause genetic mutations. These substances are known to have mutagenic effects to humans. As you look at MSDS of some chemical agents you can see these effects. Long exposure to radiation are said to bring this effect. Lastly, viruses can influence genetics.

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PLS HELP

alexandr1967 [171]

Answer:

Explanation:

A 12.48 g sample of an unknown metal, heated to 99.0 °C was then plunged into 50.0 mL of 25.0 °C water. The temperature of the water rose to 28.1 Go to calculating final temperature when mixing two samples of water ... Problem #1: A 610. g piece of copper tubing is heated to 95.3 °C and placed in an ... The two rings are heated to 65.4 °C and dropped into 12.4 mL of water at 22.3 °C. ... Problem #4: A 5.00 g sample of aluminum (specific heat capacity = 0.89 J g¯1

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2 years ago

Read 2 more answers

How many total atoms are in 0.670 g of p2o5?

scoray [572]

The molecular formula for compound is $P_{2}O_{5}$ mass of compound is 0.670 g.

To calculate number of atoms first calculate number of moles in the compound as follows:

$n=\frac{m}{M}$

Molar mass of $P_{2}O_{5}$ is 283.886 g/mol, thus,

$n=\frac{0.670 g}{283.886 g/mol}=0.00236 mol$

Thus, number of mole of $P_{2}O_{5}$ is 0.00236 mol.

From the molecular formula 1 mole of $P_{2}O_{5}$ has 2 mol of P (phosphorus) and 5 mol of O (oxygen).

Thus, number of moles of P and O in 0.00236 mol of $P_{2}O_{5}$ will be:

$n_{P}=2\times 0.00236 mol=0.00472 mol$

Similarly,

$n_{O}=5\times 0.00236 mol=0.0118 mol$

Now, in 1 mol of an element there are $6.023\times 10^{23}$ atoms.

Number of atoms of P will be:

$N_{P}=0.00472\times 6.023\times 10^{23}=2.84\times 10^{21}atoms$

Similarly, number of atoms of O will be:

$N_{O}=0.0118\times 6.023\times 10^{23}=7.11\times 10^{21}atoms$

Total number of atoms will be sum of number of atoms of P and O:

$N_{Total}=N_{P}+N_{O}=2.84\times 10^{21}+7.11\times 10^{21}=9.95\times 10^{21} atoms$

Therefore, total number of atoms in $P_{2}O_{5}$ will be $9.95\times 10^{21} atoms$ .

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2 years ago

GIVING BRAINLIEST FIVE STARS AND 25 POINTS!

jasenka [17]

Answer:

Engines can overheat for many reasons. In general, it's because something's wrong within the cooling system and heat isn't able to escape the engine compartment. The source of the issue could include a cooling system leak, faulty radiator fan, broken water pump, or clogged coolant hose.

Explanation:

HOPE IT WILL HELP U

3 0

2 years ago

Read 2 more answers

How many grams of phosphorus are in a sample of Ca3(PO4)2 that contains 50.0 g of calcium? Answer: ________ grams of phosphorus.

wel

Answer: The mass of phosphorus that is present for given amount of calcium is 28.53 g.

Explanation:

We are given:

Mass of calcium = 50 grams

The chemical formula of calcium phosphate is $Ca_3(PO_4)_2$

Molar mass of calcium = 40 g/mol

Molar mass of phosphorus = 31 g/mol

In 1 mole of calcium phosphate, 120 grams of calcium is combining with 62 grams of phosphorus.

So, 50 grams of calcium will combine with = $\frac{62}{120}\times 50=28.53g$ of phosphorus.

Hence, the mass of phosphorus that is present for given amount of calcium is 28.53 g.

6 0

2 years ago

Calculate the maximum numbers of moles and grams of H₂S that can form when 158 g of aluminum sulfide reacts with 131 g of water:

Phantasy [73]

What is Chemical Reaction?

A chemical reaction is the chemical transformation of one set of chemical components into another.

Main Content

Mass of aluminium sulfide is 158g

Mass of water is 131g

The chemical reaction: $Al_{2}S_{3} +H_{2}O _\to Al(OH)_{3} + H_{2}S$

First, balance the chemical equation

$Al_{2}S_{3} + 6H_{2}O \to 2Al(OH)_{3} + 3H_{2}S$

Aluminium sulfide has a molar mass of 150.16 g/mol and water has a molar mass of 18.02 g/mol. As a result, the moles of aluminum sulfide are computed as follows:

$n_{Al_{2}S_{3} } = \frac{Mass}{Molar mass}\\n_{Al_{2} S_{3} } = \frac{158g}{150.16g/mol} \\n_{Al_{2}S_{3} }=1.05 mol$

From the chemical reaction , the ratio of molar is 3mol $H_{2}S/1 mol Al_{2}S_{3}.$ So, the moles of hydrogen sulfide are:

$n_{H_{2} O} =\frac{131g}{18.02g/mol}$

= 7.26mol

From the chemical reaction, the molar ratio is 3 mol $H_{2}S/6$ mol $H_{2}O.$ So, the moles of hydrogen sulfide are:

Moles of $H_{2}S$ formed = 7.26 mol $H_{2}O \times \frac{3 mol H_{2}S }{6 mol H_{2} O} }$

Th liming reactant is $Al_{2}S_{3}$ beacuse the mass of $Al_{2}S_{3}$ forms less product than water. Therefore, the maximum number of moles of $H_{2}S$ is 3.15 mol. We know that molar mass of $H_{2}S$ is 34.10g/mol. So, the maximum mass of $H_{2}S$ formed is,

$m_{H_{2}S } = n_{H_{2}S } \times$ Molar mass of $H_{2}S$

= 3.15 mol $\times$ 34.10g/mol

= 107.4g

Now, multiplying the number of moles of $Al_{2}S_{3}$ by the molar ratio between $Al_2S_3$ and $H_2O$ which is 6mol $H_2O/1mol$ $Al_2S_3$ we get the number of moles of $H_2O$ reacted.