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valina [46]
3 years ago
11

*finished the test its B* In a science lab, a student heats up a chemical from 10 °C to 25 °C which requires thermal energy of 3

0000 J. If mass of the object is 40 g, the specific heat capacity of the chemical would be
Group of answer choices


100 J /g* °C


50 J /g* °C *its this one*


75 J /g* °C


25 J /g* °C
Chemistry
1 answer:
Illusion [34]3 years ago
8 0

Answer:

Yup! The answer is 50 J/g* °C

Explanation:

I also took the test but I know how to work out the problem for anyone who wants to know how to solve it.

Remember the formula q = m*C*ΔT

m = the mass in grams

C = the specific heat Capacity

ΔT = change in time

q = amount of energy

So, find out what was given and what we need to look for:

m = 40 g

C = ?

ΔT = we're heating up (the temperature increases) a chemical so it needs to be a positive number. 25 - 10 = 15 °C

q = 30000 Joules

Now, set up the equation:

q = m*C*ΔT

30000 = 40 * C * 15

Multiply 40 and 15 to get 600:

30000 = 600 * C

Divide both sides by 600 to get C by itself (plug this into your calculator):

30000/600 = 600 * C/600

You are left with 50 = C

Now, you just need to plug in the units to get B. 50 J/g* °C

I hope I helped clear up any confusion! :D

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Please answer this question!
Hunter-Best [27]

1,2-dimbromopropane would be something like C which is the second best answer.

B would be correct if it had another carbon.

A is like C but incorrect for the same reason. 1,2-dibromoethane is what A is.

The answer has to be D where the bromines are right across from each other.

3 0
3 years ago
6. Lysozyme is an enzyme that hydrolyzes sugar linkages in the bacterial cell wall and was first discovered by Alexander Fleming
balu736 [363]

Answer:

See explaination

Explanation:

The Cys3-cys97 and cys21-cys142 disulfides restrict the unfolded state of lysozyme enzyme to a class of more compact structures with a less exposed hydrophobic surface, compared to the unfolded states of reduced/non-crosslinked lysozyme. there are 2 major factors which lead to the stabilization of lysozyme due to disulfide bonds-

1- increase in the loop size due to the formation of disulfide bonds that leads to an increase in the even entropic effect.

2- the region formed should be flexible. the strain energy due to the formation of the disulfide bond is lower.

cys21-cys142 has a higher Tm than the cys3-cys97 because it involves flexible parts of the molecule. 21 and 142 residues are located on opposite sides of the active-site cleft where significant hinge-bending motion is seen. this introduces minimal strain in the protein.

7 0
3 years ago
The combustion of butane produces heat according to the equation 2C4H10(g) + 13O2(g) → 8CO2(g) + 10H2O(l), ΔH°rxn= –5,314 kJ/mol
Dafna11 [192]

Answer:

665 g

Explanation:

Let's consider the following thermochemical equation.

2 C₄H₁₀(g) + 13 O₂(g) → 8 CO₂(g) + 10 H₂O(l), ΔH°rxn= –5,314 kJ/mol

According to this equation, 5,314 kJ are released per 8 moles of CO₂. The moles produced when 1.00 × 10⁴ kJ are released are:

-1.00 × 10⁴ kJ × (8 mol CO₂/-5,314 kJ) = 15.1 mol CO₂

The molar mass of CO₂ is 44.01 g/mol. The mass corresponding to 15.1 moles is:

15.1 mol × 44.01 g/mol = 665 g

4 0
3 years ago
A sucrose solution is prepared to a final concentration of 0.250 M . Convert this value into terms of g/L, molality, and mass %.
MArishka [77]

Answer:

A. 85.6 g

= 0.0856 kg.

B. 0.00027 mol/g

= 0.27 mol/kg.

C. 8.39 %

Explanation:

Given:

Molar concentration = 0.25 M

Molar weight of sucrose = 342.296 g/mol

Density of solution = 1.02 g/mL

Mass of water = 934.4 g.

Density in g/l = 1.020 g/ml * 1000ml/1 l

= 1020 g/l

Mass of solution in 1 l of solution = 1020 g

Mass of solution = mass of solvent + mass of solute

Mass of sucrose = 1020 - 934.4

= 85.6 g of sucrose in 1 l of solution.

A.

Density of sucrose = mass/volume

= molar mass/molar concentration

= 342.296 * 0.25

= 85.6 g/l

Number of moles = mass/molar mass

= 85.6/342.296

= 0.25 mol

B.

Molality = number of moles of solute/mass of solvent

= 0.25/934.4

= 0.00027 mol/g

C.

% mass of sucrose = mass of sucrose/total mass of solution * 100

= 85.6/1020 * 100

= 8.39 %

6 0
3 years ago
Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. The energy of one photon of this
Sedbober [7]

<u>Answer:</u> The energy of one photon of the given light is 3.79\times 10^{-19}J

<u>Explanation:</u>

To calculate the energy of one photon, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

\lambda = wavelength of light = 525nm=5.25\times 10^{-7}m        (Conversion factor:  1m=10^9nm  )

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

Putting values in above equation, we get:

E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{5.25\times 10^{-7}mm}\\\\E=3.79\times 10^{-19}J

Hence, the energy of one photon of the given light is 3.79\times 10^{-19}J

3 0
3 years ago
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