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2 years ago

Please help me with this math problem!! Will give brainliest!! NO LINKS PLEASE!! Thanks!! :)

Mathematics

1 answer:

Lady_Fox [76]2 years ago

8 0

Answer:

x = 3

So,

PQ= 5

RS=6

Step-by-step explanation:

Hope it helps you.....

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reduce the following fractions to their lowest terms: a. 6/8. b. 8/12c. 15/20 d. 9/18 e. 24/30 f. 25/40

Murljashka [212]

Answer:

That's my slovings for your question

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3 years ago

Expression A: 4x + 5 Expression B: 2 + 4x + 3 Which statement can be used to show that these expressions are equivalent?

Alexandra [31]

Answer:

Step-by-step explanation:

3 0

3 years ago

Please help... I have no clue

muminat

Answer:

OPTION C: Sin C - Cos C = s - r

Step-by-step explanation:

ABC is a right angled triangle. ∠A = 90°, from the figure.

Therefore, BC = hypotenuse, say h

Now, we find the length of AB and AC.

We know that: $\textbf{Sin A} = \frac{\textbf{opp}}{\textbf{hyp}}$

and $\textbf{Cos A} = \frac{\textbf{adj}}{\textbf{hyp}}$

Given, Sin B = r and Cos B = s

⇒ $Sin B = r = \frac{opp}{hyp} = \frac{AC}{BC} = \frac{AC}{h}$

⇒ $\textbf{AC} = \textbf{rh}$

Hence, the length of the side AC = rh

Now, to compute the length of AB, we use Cos B.

$Cos B = s = \frac{adj}{hyp} = \frac{AB}{BC} = \frac{AB}{h}$

⇒ $\textbf{AB} = \textbf{sh}$

Hence, the length of the side AB = sh

Now, we are asked to compute Sin C - Cos C.

$Sin C = \frac{opp}{hyp}$

⇒ $Sin C = \frac{AB}{BC}$

$= \frac{sh}{h}$

= s

Sin C = s

$Cos C = \frac{adj}{hyp}$

$\implies Cos C = \frac{AC}{BC}$

⇒ Cos C = $\frac{rh}{h}$

Therefore, Cos C = r

So, Sin C - Cos C = s - r, which is OPTION C and is the right answer.

5 0

3 years ago

4. Write an equation for the line that is parallel to the given line and that passes

pentagon [3]

Answer:

$y=\frac{5}{2}x-14$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0)
Parallel lines always have the same slope

1) Determine the slope (m)

$y=\frac{5}{2}x-10$

In the given equation, $\frac{5}{2}$ is in the place of m, making it the slope. Because parallel lines have the same slope, the line we're currently solving for therefore has a slope of $\frac{5}{2}$ . Plug this into $y=mx+b$ :