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Paha777 [63]
2 years ago
9

Let A and B be two events. Suppose that P(A) = 0.21 and P(B) = 0.60.

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
4 0

Answer For two events A and B,P(A)−0.36,P(B)−0.37, and P(A∩B)−0.11 a. Find P(A∣B). b. Find P(B∣A). c. Determine whether or not A and Bare independent. I think

Step-by-step explanation:

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Answer:

Two possible lengths for the legs A and B are:

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Step-by-step explanation:

For a triangle rectangle, Pythagorean's theorem says that the sum of the squares of the cathetus is equal to the hypotenuse squared.

Then if the two legs of the triangle are A and B, and the hypotenuse is H, we have:

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If we know that H = 15cm, then:

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Now we can just input different values of B there, and then solve the value for the other leg.

Then if we have:

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Then we could have:

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Now let's try with another value of B:

if B = 9cm, then:

A = √( (15cm)^2 - (9cm)^2) = 12 cm

Then we could have:

B = 9cm

A = 12cm

So we just found two possible lengths for the two legs of the triangle.

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