Please answer ASAP. Suppose we write down the smallest (positive) 2-digit, 3-digit, and 4-digit multiples of 8.
2 answers:
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The solution to the given system is (3,8).
<u>Step-by-step explanation:</u>
To draw a graph system for a linear equation,
Step 1: Consider two x values and draw a line joining the new points.
y = x + 5 ⇒1
y = 2x + 2 ⇒2
For both equations substitute two random values for x.
Let us Consider x=0 and x=10.
For equation 1,
y=x+5. y=x+5
y=0+5. y=10+5
y=5 y=15
The new points for equation 1 are (0,5) and (10,15).
Draw a big straight line passing through these two points.
For equation 2,
y=2x+2. y=2x+2
y=0+2. y=20+2
y=2 y=22.
The new points for equation 1 are (0,2) and (10,22).
Again, draw a big straight line passing through these two points.
Step 2: Mark the intercepting point and that will be the solution for the given system.
For this system, the solution is (3,8).
To check this answer equate both equations,
x+5=2x+2.
2x-x=5-2.
x=3.
Substitute x value in any of the equation,
y=3+5.
y=8.
So the resulted point is (3,8).
Rewrite the term
Expand each term so we have
Use the fact that
Use the fact that when a is an even number
Simplify
Let me know if you need any clarifications, thanks!