a(x+1)(x-1)+b(x-2)(x+1)+(x+1)^2=9x^2-x-10
(x+1)(a(x-1)+b(x-2)+(x+1))=(x+1)(9x-10)
a(x-1)+b(x-2)+x+1=9x-10
Now this equation is much simpler!
(a+b)x-a-2b+x+1=9x-10
(a+b)x-a-2b=8x-11
(a+b-8)x-a-2b-11=0
a+b-8=(a+2b-11)/x
I can't solve it 3 variables and 1 equations means infinite answers so yea.
<u><em>FALSE.</em></u><em></em>
A composite number is the opposite of a prime number. This is false because of the possibility of the following scenario:
The two numbers are 1 and a prime number.
This is because <em>one multiplied by any number is that number.</em> A prime number cannot become a composite number just because it is being multiplied by one. For example:
1 x 7 = 7 (prime)
Hope this helps!
~<em>Archimedes El</em>∈<em>ven</em>
Answer:
y = 3x -4
Step-by-step explanation:
The slope-intercept equation looks like this: 
. Where m is the slope of the function and b is the y-coordinate of the vertical intercept (where the function crosses the y-axis). Let's apply the formula:
Let the number = x.
So 2 times x subtracted from 11 is written as 11-2x
The result is 4 more than the number is written as 4 +x
Now you have 11-2x = 4 + x
We can now solve for x.
Add 2x to each side:
11 = 4 + 3x
Subtract 4 from each side:
7 = 3x
Divide both sides by 3:
x = 7/3
You have to multiple b× w×h. the answer would be 342
