Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²
Answer:
(-1, -2)
Step-by-step explanation:
Find the <em>x</em>-value the minimum occurs at. Use this value to find the minimum value. (Graph to find the highest point)
Y=MX+B
Y= 2X+50
And we don’t know how long they are getting towed but when we find that out we plug it into X
Natural 9,53
whole 0,9,53
integers -14,9,0,53,-626
+integers 9,53
-integers -14,-626
