Answer:
a. 96 square units
Step-by-step explanation:
The figure is a rectangle with width AB = (20-12) = 8 units and height BC = (20-8) = 12 units.
The area of the rectangle is (8 units)×(12 units) = 96 square units.
t_o = 3, so solution exists on (0,4).
Use Theorem
Divide equation with t(t — 4).
y''+[3/(t-4)]*y'+ [4/t(t-4)]*y=2/t(t-4)
p(t)=3/t-4—> continuous on (-∞, 4) and (4,∞)
q(t) = 4/t(t-4) —> continuous on (-∞,0), (0,4) and (4, ∞)
g(t) = 2/t(t-4)—> continuous on (-∞, 0), (0,4) and (4,∞)
equals nothing. cannot be multiplied or divided. does not change a number when added or subtracted
The answer is –x + 5 = 6x - 2. This is because of the Transitive Property.
You most likely remember the transitive property as "if a = b and b = c, then a = c." In this case, if y = -x + 5 and y = 6x - 2, then -x + 5 = 6x - 2.
the first one but make sure to divide
