A role-playing game uses an 11-sided die that displays the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 What is the probability tha
kondor19780726 [428]
Using it's concept, it is found that there is a 27.3% probability that someone throws the 11-sided die one time and rolls a number 9 or higher.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, there are 11 numbers, 3 of which are 9 or higher, hence the probability is:
p = 3/11 = 0.273 = 27.3%.
More can be learned about probabilities at brainly.com/question/14398287
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Answer:
z < 2
Step-by-step explanation:
um im not sure let me known if it's right
The answer is 5/12 because 1/6 converts to 2/6 and 7/12-2/6 is equal to 5/12
Answer:
4
Step-by-step explanation:
if there is 8 games in 2 weeks, that means there is 4 games a week
16 games would equal 4 games a week
create an equation
16=4x
4x is the number of games per week
16=number of games
divide to isolate x and you get 4
