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Damm [24]
3 years ago
14

PLEASE HELP ME RN, IM DOING A QUIZ!

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
4 0

Step-by-step explanation:

you need to show us f(x)=log x graph so we can help

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I need this for a test; help asap
weqwewe [10]

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SHAKE A LIL A** FA DA MONEY I GET MONEY YEA YEAAAAAA

Step-by-step explanation:

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PLEASE HELP Aria made 9 pounds of fudge.She separates the fudge into 3/4 pound portions. She sells each portions for $6.50.if sh
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6 0
3 years ago
What is the equation of the circle with center (-3.2, -2.1) and radius 4.3?
Ilya [14]

The equation of the circle is :  x^{2} + y^{2} + 6.4x + 4.2y = 3.84

<h3>Meaning of a Circle</h3>

A circle is a loci or a continuous line that equidistant from the center to any point on the line. it drawn starting from a point and ending on that same  point.

The equation of a circle is an equation used to find points on a circle so the circle can be drawn with accurate measurement. it can also be used to find the missing points.

In conclusion, The equation of the circle is :  x^{2} + y^{2} + 6.4x + 4.2y = 3.84

Learn more about equation of a circle: brainly.com/question/1506955

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6 0
2 years ago
The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop
Anettt [7]

Answer:

a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

a. Favorable cases for Both the laptops to be selected = _2C_2 = 1

Total number of cases = 15

Required probability is \frac{1}{15}.

b. Favorable cases for both the desktop machines selected = _4C_2=6

Total number of cases = 15

Required probability is \frac{6}{15} = \frac{2}{5}.

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

2. Both desktop:

Favorable cases = _4C_2=6

Total number of favorable cases = 8 + 6 = 14

Required probability is \frac{14}{15}.

d. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

Total number of cases = 15

Required probability is \frac{8}{15}.

8 0
4 years ago
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