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Anestetic [448]

2 years ago

13

Hannah is experimenting with a new drawing program on her computer. She created quadrilateral MATH with coordinates M(1, 2). A(-

5, 3), T(- 6,-3), and H(0,- 4). Hannah believes that she has created a square. Prove that Hannah is correct.

1 answer:

Dovator [93]2 years ago

8 0

Answer:

It is a square, Hannah is a G.

Step-by-step explanation:

You can plug it in for visual, see attachment. You can see that it is a bit rotated square.

But real proof should be done with the points.

For it to be square all sides need to equal each other.

What's the x distance of M and A?

It is 1-(-5) = 1+5 = 6

What is the x distance of H and T?

It is 0-(-6) = 0+6 = 6

What is the y distance of M and H?

It is 2-(-4) = 2+4 = 6

What is the y distance of A and T?

It is 3-(-3) = 3+3 = 6

All are 6 so all sides are equal so it is a square.

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How to simplify this problem: (4c^4)^3

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Answer:

64c^12

Step-by-step explanation:

(4c^4)^3 distribute exponents

{(4)^3 (C^12)} simplify

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3 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

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Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

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3 years ago

Brainliest if you are correct

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Answer:

D) $log_2(x)+3log_2(9)$

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4x(3x²+5y) expand by distributing terms

4x*3x²+4x*5y take out the constants

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12xx²+4x*5y use product rule=xᵃxᵇ=xᵃ+ᵇ, and change the two variables (the x's) into ones, because if there is just one variable with no number by it, then it is a one.

12x¹⁺²+4x*5y and simplify 1+2 to 3.

12x³+4x*5y finally simplify 4x*5y to 20xy

12x³+20xy

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