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3 years ago

For the reaction H2O) =H% + OH", if x moles of H and y moles of OH are formed K. is y A. *?/(1 – x) C. 1/xy D. xy

Chemistry

1 answer:

hjlf3 years ago

5 0

Answer: Correct option is B)

The standard enthalpy change of formation of a compound is the enthalpy change which occurs when one mole of the compound is formed from its elements under standard conditions. The equation showing the standard enthalpy change of formation of water is

H
2
(g)+

2
1

 O

 (g)⟶H

2 ↑

 O(l) 1 mole of water formed.

∴ Enthalpy of formation is −X2kJ/mol.

________________________________________________________

Explanation:I hope this helped

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State any two non-industrial uses of hydrogen gas (2mks)<br>

Brut [27]

Answer:

Petroleum and treating meals.

3 0

2 years ago

What is the molarity of a solution that is 26.0% by mass in phosphoric acid, H3PO4, and that has a density of 1.155 g/mL?

steposvetlana [31]

Answer: The molarity of a solution that is 26.0% by mass in phosphoric acid is 3.06 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

n = moles of solute

$V_s$ =volume of solution in ml

Given : 26.0 g of phosphoric acid in 100 g of solution.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{26.0g}{98g/mol}=0.265moles$

Volume of solution = $\frac{\text {Mass of solution}}{\text {Density of solution}}=\frac{100g}{1.155g/ml}=86.6ml$

$Molarity=\frac{0.265\times 1000}{86.6ml}=3.06M$

Molarity of a solution that is 26.0% by mass in phosphoric acid is 3.06 M

8 0

3 years ago

A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal

bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}$

$\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}$

Solving for V₂ , we get:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

4 0

4 years ago

I NEED HELP PLEASE! :)

riadik2000 [5.3K]

Answer:

$C_{21} H_{23} NO_{5}$

Explanation:

First thing is we have assume all the percents are grams so we have

68.279g C, 6.2760g H, 3.7898g N, and 21.656g O

Now convert each gram to moles by dividing the the molar mass of each element

68.279g/12.01g= 5.685 moles of C

6.2760g/1.01g= 6.214 moles of H

3.7898g N/14.01g= 0.271 moles of N

21.656g O/ 16.00g= 1.354 moles of O

Now to find the lowest ratios divide all the moles by the smallest number of moles you found, in our case, the smallest moles is 0.271 moles of N so divide everything by that....

5.685 moles/0.271 moles ------> ~21 C

6.214 moles/0.271 moles --------> ~23 H

0.271 moles / 0.271 moles ---------> 1 N

1.354 moles/ 0.271 moles ----------> ~5 O

So the empirical formula is C21H23NO5 $C_{21} H_{23} NO_{5}$

5 0

3 years ago

Which of the following is not a renewable resource

BabaBlast [244]

Natural gas is nonrenewable, once its used you have to get more, after its all used up you cant use it no more.

4 0

4 years ago

For the reaction H2O) =H% + OH", if x moles of H and y moles of OH are formed K. is y A. *?/(1 – x) C. 1/xy D. xy ​

For the reaction H2O) =H% + OH", if x moles of H and y moles of OH are formed K. is y A. *?/(1 – x) C. 1/xy D. xy