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2 years ago

For the reaction H2O) =H% + OH", if x moles of H and y moles of OH are formed K. is y A. *?/(1 – x) C. 1/xy D. xy

Chemistry

1 answer:

hjlf2 years ago

5 0

Answer: Correct option is B)

The standard enthalpy change of formation of a compound is the enthalpy change which occurs when one mole of the compound is formed from its elements under standard conditions. The equation showing the standard enthalpy change of formation of water is

H
2
(g)+

2
1

 O

 (g)⟶H

2 ↑

 O(l) 1 mole of water formed.

∴ Enthalpy of formation is −X2kJ/mol.

________________________________________________________

Explanation:I hope this helped

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A compound contains only change and n combustion of 35.0mg of the compound produces 33.5mg co2 and 41.1mg h2o. What is the empir

Viefleur [7K]

Answer:

The empirical formula is CH6N2

Explanation:

A compound containing only C, H, and N yields the following data. Complete combustion of 35.0 mg of the compound produced 33.5 mg of CO2 and 41.1 mg of H2O. What is the empirical formula of the compound

Step 1: Data given

Mass of the compound = 35.0 mg = 0.035 grams

Mass of CO2 = 33.5 mg = 0.0335 grams

Mass of H2O = 41.1 mg = 0.0411 grams

Molar mass CO2 = 44.01 g/mol

Molar mass H2O = 18.02 g/mol

Molar mass C = 12.01 g/mol

Molar mass O = 16.0 g/mol

Molar mass H = 1.01 g/mol

Step 2: Calculate moles CO2

Moles CO2 = 0.0335 grams / 44.01 g/mol

Moles CO2 = 7.61 *10^-4 moles

Step 3: Calculate moles C

For 1 mol CO2 we have 1 mol C

For 7.61 *10^-4 moles CO2 we have 7.61 *10^-4 moles C

Step 4: Calculate mass C

Mass C = 7.61 *10^-4 moles * 12.01 g/mol

Mass C = 0.00914 grams = 9.14 mg

Step 5: Calculate moles H2O

Moles H2O = 0.0411 grams / 18.02 g/mol

Moles H2O = 0.00228 moles

Step 6: Calculate moles H

For 1 mol H2O we have 2 moles H

For 0.00228 moles H2O we have 2* 0.00228 = 0.00456 moles H

Step 7: Calculate mass H

Mass H = 0.00456 moles * 1.01 g/mol

Mass H = 0.00461 grams = 4.61 mg

Step 8: Calculate mass N

Mass N = 35.0 mg - 9.14 - 4.61 = 21.25 mg = 0.02125 grams

Step 9: Calculate moles N

Moles N = 0.02125 grams / 14.0 g/mol

Moles N = 0.00152 moles

Step 10: Calculate the mol ratio

We divide by the smallest amount of moes

C: 0.000761 moles / 0.000761 moles= 1

H: 0.00456 moles / 0.000761 moles = 6

N: 0.00152 moles / 0.000761 moles = 2

For every C atom we have 6 H atoms and 2 N atoms

The empirical formula is CH6N2

5 0

3 years ago

What is the name of the following compound? A line-angle formula shows a ring with six vertices and a circle inscribed. A Cl ato

ozzi

Answer: Option C. p-dichlorobenzene and 1,4-dichlorobenzene.

Explanation:

A line-angle formula with six vertices and a circle inscribed corresponds to the compound known as benzene.

Further, according to the IUPAC standards for naming benzene derivatives, you must first number the position of the substituent. In this case, the substituents (chloros) are located at the positions 1 and 4; also, for the benzene derivatives when they have 2 substituents and the positions are 1 and 4, this configuration is known as para or p configuration.

Additionally, this compound has 2 substituents (chloros) so you have to indicate this number (di).

Therefore, the correct answer is C. p-dichlorobenzene and 1,4-dichlorobenzene.

4 0

3 years ago

Which of the following statements is true about the composition of the atmosphere?

Phoenix [80]

Answer : Option D) The atmospheric conditions vary as one changes latitude and altitude.

Explanation : The composition of the atmosphere varies according to the latitude and altitude because of the unequal heating of the earth surface at different latitudes and altitudes which results into atmospheric changes. It also creates different regions and zones.

3 0

3 years ago

Read 2 more answers

A 50-mL beaker only has a scale that measures 10, 20, 30, and 40 mL. What is the uncertainty associated with the 50 mL beaker.

Juliette [100K]

If the uncertainty of a certain measurement instrument is not given, then it is assumed to be equal to half of the least count of that instrument. In this case, the least count is 10 ml, so half of this is 5 ml. Therefore, the graduated cylinder has an uncertainty of +/- 5 ml

8 0

3 years ago

8. What is the heat of reaction when hydrogen and oxygen combine to form water?

valina [46]

Answer:

The heat of reaction when hydrogen and oxygen combine to form water is :

C. 571.6 kJ

Explanation:

Enthalpy Change = The enthalpy change for the formation of 1 mole of the substance from their standard state is called the enthalpy of formation.

This is intensive quantity as it is fixed for 1 mole .

Intensive properties = Those properties which are independent on the amount of the substance are intensive properties.

The value of these quantities does not get halve if you divide the substance into two equal parts. example , density, refractive index.

However , the enthalpy of reaction is extensive. Because on increasing the amount the value of the enthalpy also get doubles

Hence for this reaction :

$2H_{2}(g)+O_{2}\rightarrow 2H_{2}(l)$

Its value is -285.8 kJ for 1 mole

And here two moles are present . so the value of molar enthalpy is:

-285.8 x 2 = -571.6 kJ

8 0

3 years ago

For the reaction H2O) =H% + OH", if x moles of H and y moles of OH are formed K. is y A. *?/(1 – x) C. 1/xy D. xy ​

For the reaction H2O) =H% + OH", if x moles of H and y moles of OH are formed K. is y A. *?/(1 – x) C. 1/xy D. xy