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3 years ago

If a piece of metal were to cut in half would the density change

2 answers:

8 0

Density depends on both the mass and the volume of an object. If you cut a bar of gold in half, you would have two bars with half the mass of the original bar. However, each bar would also have half the volume of the original bar. The density of gold does not change.

yanalaym [24]3 years ago

8 0

No, the density is the same even if it's cut in half or how ever many pieces.

so the metal would be the same.

Thanks,

Deku ❤

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Which of the following is an oxidation-reduction reaction? so2(g) h2o(l) right arrow. h2so3(aq) caco3(s) right arrow. cao(s) co2

Gennadij [26K]

The reaction which shows oxidation and reduction simultaneously is C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(l).

<h3>What are redox reactions?</h3>

Those reaction in which oxidation as well as reduction of substances takes place simultaneously will known as redox reactions.

SO₂(g) + H₂O(l) → H₂SO₃(aq)
CaCO₃(aq) → CaO(s) + CO₂(g)
Ca(OH)₂(s) + H₂CO₃(l) CaCO₃(aq) + 2H₂O(l)

Above reaction are not the redox reactions as in these reaction oxidation and reduction simultaneously not takes place.

C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(l)

In the above reaction reduction of oxygen takes place as its oxidation state changes from 0 to -2, and at the same time oxidation of carbon takes place as its oxidation state changes from 0 to +4.

Hence correct option is (4).

To know more about redox reactions, visit the below link:
brainly.com/question/7935462

7 0

2 years ago

Read 2 more answers

Calculate the amount of heat deposited on the skin of a person burned by 1.00g of steam at 100.0C. Skin temperature is 37C. ΔHva

seraphim [82]

The amount of heat deposited on the skin is 2.26 kJ.

<h3>What is the amount of heat given off by 1.0 g of steam?</h3>

The amount of heat given off by steam is determined using the formula below:

Quantity of heat = mass * latent heat of vaporization.

Moles of steam = 1.0/18

Heat = 1.0/18 * 40.7

Heat deposited = 2.26 kJ

In conclusion, the quantity of heat is determined from the latent heat of vaporization and the moles of steam.

Learn more about heat of vaporization at: brainly.com/question/26306578

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7 0

2 years ago

Please somebody give me the answers

RSB [31]

Answer:

1. 9.4 grams of methane produce 25.85 grams of CO2

2.Grams of water produced = 11.81 grams

3.Mass of Methane produced by 10.1 gram of O2 = 2.52 grams

4.Amount of methane consumed = 46.9 grams

5. Grams of Co2 produced = 8.32 grams

Explanation:

Molar masses :

Methane = CH4 = mass of C + 4x (mass of H)

CH4 = 12 +4(1) = 16 grams

1 mole of CH4 = 16 gram

Oxygen O2 = 2 x (mass of O) = 2x(16) = 32 gram (1 mole of O2 =32 gram)

Carbon Dioxide =CO2 = mass of C + 2(mass of O)

= 12 + 2(16)

= 44 grams (1 mole of CO2 = 44 gram )

Water = H2O = 18 grams ( 1 mole of H2O = 18 gram)

1 mole of each molecule is equal to their molar masses

The balanced equation is :

$1CH_{4}(g)+2O_{2}\rightarrow 1CO_{2}+2H_{2}O(l)$

According to Stoichiometry :

1 mole of CH4 = 2 Mole of O2 = 1 mole of CO2 = 2 mole of H2O

1. From the equation ,

1 mole of methane produce =1 mole of CO2

16 gram of methane = 44 gram of CO2

1 gram of methane =

$\frac{44}{16}$ gram of CO2

9.4 gram of CH4 =

$\frac{44}{16}\times 9.4$ gram of CO2

= 25 .85 gram of CO2

2 mole of O2 produces = 2 mole of H2O(water)

1 mole of O2 produces = 1 mole of H2O

32 gram of O2 = 18 gram of water

1 gram of O2 =

$\frac{18}{32}$

21 gram of O2 =

$\frac{18}{32}\times 21$

11.81 gram of water

3. 1 mole of CH4 = 2 mole of O2

16 gram of CH4 = 2(32) = 64 grams of O2

64 gram of O2 needs = 16 grams of CH4

1 gram of O2 needs =

$\frac{16}{64}$

10.1 gram of O =

$\frac{16}{64}\times 10.1$ of CH4

= 2.52 gram

1 mole of CO2 is produced from = 1 mole of CH4

44 gram of CO2 is produced from 16 gram of CH4

1 gram CO2 =

$\frac{16}{44}$ gram of CH4

129 gram of CO2 =

$\frac{16}{44}\times 129$ gram of CH4

= 46.90 grams

2 mole of O2 produce = 1 mole of CO2

2x 32 gram of O2 = 44 gram of CO2

1 gram of O2 =

$\frac{44}{64}$ of CO2

12.1 gram of O2 produce=

$\frac{44}{64}\times 12.1$ of CO2

= 8.318 gram

Note : Write the quantity give on left side of "="

write the substance asked on right side of "="

8 0

3 years ago

Calculate the percent mass of sugar in mountain dew: The total mass of the mountain dew solution is 300g and there are 231 g of

s2008m [1.1K]

Answer:

c. 77 %

Explanation:

Percent mass (% mass) of solute = mass of solute/mass of solution × 100

According to this question, a mountain dew solution weighing 300grams contains 231 g of sugar. This means that:

% mass of sugar = 231g/300g × 100

% mass of sugar = 0.77 × 100

% mass of sugar = 77%.

4 0

2 years ago

What volume of a 6.67 M NaCl solution contains 3.12 mol NaCl

jonny [76]

What's the big M? Molecular weight or mol?

5 0

3 years ago