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Llana [10]
3 years ago
5

A main group element with the valence electron configuration 3s23p1 is in periodic group __________. It forms a monatomic ion wi

th a charge of ________.
A main group element with the valence electron configuration 4s24p5 is in periodic group _________. It forms a monatomic ion with a charge of __________ .
Chemistry
1 answer:
DochEvi [55]3 years ago
4 0

Answer:

Follows are the solution to this question:

Explanation:

Please find the complete question in the attachment file.

In option a)

In the periodic group of 3s^2 \ 3p^1 main group component to valence electronic structure (IIIA group) and Aluminum (Al). The monatomic ion forms a load of (+3)

In option b)

The Chlorine within the periodic group (VIIA group) is the main group element for valence electron configuration 3s^2\ 3p^5 (Cl). It constitutes a monatomic ion with a load of (-1).

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Describe the chemical reaction based on the chemical equation below. Also, explain whether the equation is balanced.
Allushta [10]

Answer:

Chemical equation: NH₃(g) + O₂(g) → NO(g) + H₂O(l).

Oxidation reaction: N⁻³ → N⁺² + 5e⁻ /×4.

Reduction reaction: O₂⁰ + 4e⁻ → 2O⁻² /×5.

Oxidation reaction: 4N⁻³ → 4N⁺² + 20e⁻.

Reduction reaction: 5O₂⁰ + 20e⁻ → 10O⁻² /×5.

Balanced chemical equation: 4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l).

Ammonia (NH₃) reacts with oxygen (O₂) and form nitrogen(II) oxide (NO) and water (H₂O). Catalyst is this reaction is platinum (Pt).

This is combustion reaction.

5 0
4 years ago
Read 2 more answers
For the general reaction aA + bB cC + DD, has the general rate law, rate k[A] [B].". What is the
nataly862011 [7]

Answer:

K=CHANGE IN CONCENTRATION/TIME TAKEN

Explanation:

7 0
3 years ago
Examples of non polar covalent bonds
ikadub [295]

Answer:

# The simpliest is: H-H

# All gases formed by elements of the 7th group in the periodic table:

  F-F,   Cl-Cl, Br-Br, I-I

# In general, Covalent bonds formed between atoms of the same kind are usually non-polar.

Explanation:

Hope this answer will help you.

4 0
3 years ago
Consider the following molecule.<br> 1. How many bonding pair of electrons are present?
Artemon [7]

Answer:

There are 3 bonding pairs of electrons

Explanation:

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5 0
3 years ago
How many moles of solute are in 300 mL of 1.5 M CaCl2? How many grams fo CaCl2 is this?
tester [92]

Answer:

1. 0.45 mole

2. 49.95g

Explanation:

The following were obtained from the question:

Volume of solution = 300mL = 300/1000 = 0.3L

Molarity = 1.5 M

Mole of CaCl2 =?

1. We can obtain the mole of the solute as follow:

Molarity = mole of solute /Volume of solution

1.5 = mole of solute/0.3

Mole of solute = 1.5 x 0.3

Mole of solute = 0.45 mole

2. The grams in 0.45 mole of CaCl2 can be obtained as follow:

Molar Mass of CaCl2 = 40 + (35.5 x 2) = 40 + 71 = 111g/mol

Mole of CaCl2 = 0.45 mole

Mass of CaCl2 =?

Mass = number of mole x molar Mass

Mass of CaCl2 = 0.45 x 111

Mass of CaCl2 = 49.95g

3 0
3 years ago
Read 2 more answers
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