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dolphi86 [110]
3 years ago
5

students planted 4(2x+3y) amount of trees on saturday and then 3(5x+4) amount of trees on Sunday. What is the total amount of tr

ees that the students planted?
Mathematics
1 answer:
Reika [66]3 years ago
3 0
35x plus 12 

you cannot add them since they are not like terms 
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There were 7 inches of rain in 24 hours. What is the average amount of rain per hour ​
Mademuasel [1]

Answer:

7 /24 inch per hour

Step-by-step explanation:

To find the average amount of rain, take the total amount of rain and divide by the time

7 inches / 24 hours

7 /24 inch per hour

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Which table represents a linear function?
zloy xaker [14]

Answer: 4th table

Step-by-step explanation:

Each time x increases by 1, y increases by 2. Since there is a constant increase in y for each time x increases by 1, the table represents a linear function.

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How do you long divide step by step
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https://www.wikihow.com/Do-Long-Division

Step-by-step explanation:

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3 years ago
Which linear inequality is graphed with y >x-2 to
jek_recluse [69]

Answer:

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3 years ago
Find all solutions of the equation: 2cos^2x-cosx=1
Art [367]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/3166243

——————————

Solve the trigonometric equation:

     \mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}


Make a substitution:

     \mathsf{cos\,x=t\qquad (-1\le t\le 1)}

and the equation becomes

     \mathsf{2t^2-t-1=0}


Rewrite conveniently  – t  as  + t – 2t,  and then factor the left-hand side by grouping:

      \mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}


Factor out  2t + 1:

     \mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}


Substitute back for  t = cos x:

     \begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}


Therefore,

     \begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}

where  k  is an integer.


Solution set:   

\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}


I hope this helps. =)

3 0
3 years ago
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