Question

Complete the synthetic division problem below.

Answer 1

Answer:

B

Step-by-step explanation:

This was originally a third degree polynomial:

$2x^3+4x^2-4x+6$, to be exact.

When you divide by -3, you are basically trying to determine if x + 3 is a zero of that third degree polynomial.  The quotient is always one degree lesser than the polynomial you started with, and if there is no remainder, then x + 3 is a zero of the polynomial and you could go on to factor the second degree polynoial completely to get all 3 solutions.  To perform the synthetic division, you always first bring down the number in the first position, in our case a 2.  Then multiply that 2 by -3 to get -6.

-3|  2   4   -4   6

          -6

    2    -2

So far this is what we have done.  Now we multiply the -3 by the -2 and put that up under the -4 and add:

-3|  2   4   -4   6

          -6   6

    2    -2   2

Now we multiply the -3 by the 2 to get -6 and put that up under the 6 and add:

-3|   2   4   -4   6

           -6    6  -6

      2    -2   2   0

That last row gives us the depressed polynomial, which as stated earlier here, is one degree less than what you started with:

$2x^2-2x+2$

Answer 2

Answer: OPTION B

Step-by-step explanation:

You need to follow these steps:

- Carry the number 2 down and multiply it by the the number -3.

- Place the product obtained above the horizontal line, below the number 4 and add them.

- Put the sum below the horizontal line.

- Multiply this sum by the number -3.

- Place the product obtained above the horizontal line, below the number -4 and add them.

- Put the sum below the horizontal line.

- Multiply this sum by the number -3.

- Place the product obtained above the horizontal line, below the number 6 and add them.

Then:

$-3\ |\ 2\ \ \ \ \ 4\ \ -4\ \ \ \ \ \ 6\\\.\ \ \ \ \ |\ \ \ \ -6\ \ \ \ \ 6\ \ \ -6$

$-----------------$

$.\ \ \ \ \ \ 2\ \ \ -2\ \ \ \ 2\ \ \ \ \ 0$

 Therefore, the quotient in polynomial form is:

$2x^2-2x+2$