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3 years ago

According to the _____ model, the solar system formed from a cloud of dust and gas.

2 answers:

4 0

The correct answer to the question above is nebular. According to the NEBULAR model, the solar system formed from a cloud of dust and gas. Nebula model is a hypothesis in which tells you the origin (formation and evolution) of the solar system.

weqwewe [10]3 years ago

3 0

Answer:

According to the <u>NEBULAR</u> model, the solar system formed from a cloud of dust and gas.

Explanation:

According to Nebular model, the solar system was formed from molecular cloud of dust and gases. The material accreted and collapsed under its own weight. The rotating core gathered more mass increasing its temperature and pressure until nuclear fusion reaction started and Sun was born. The rest of the material flattened into disk from which planets were formed.

You might be interested in

How many joules of work are done on an object when a force of 10 N pushes it 5 m?

zhenek [66]

Answer:

option C

Explanation:

given,

Force on the object = 10 N

distance of push = 5 m

Work done = ?

we know,

work done is equal to Force into displacement.

W = F . s

W = 10 x 5

W = 50 J

Work done by the object when 10 N force is applied is equal to 50 J

Hence, the correct answer is option C

5 0

3 years ago

A parallel beam of light containing orange (610 nm) and violet (410 nm) wavelengths goes from fused quartz to water, striking th

Fudgin [204]

Answer:

0.98°

Explanation:

First we find the refracting angle of orange in water

Which is given as

စr= sin^-1. ( 1.456 sin60°/1.33)

= 71.2°

Then that of violet in water

စv=sin^-1. ( 1.468sin60°/1.342)

= 72.3°

So angle between boths colours is the difference

71.2- 72.3= 0.98°

6 0

3 years ago

If size of an image is 10 cm and the magnification produced by a mirror is +1, what will be the size of object?

olya-2409 [2.1K]

Answer:

h = 10 cm

Explanation:

The magnification produced by a mirror is given by :

$m=\dfrac{h'}{h}$

h' is the image size and h is the object size

We have, h = 10 cm, m = +1

So,

$m=\dfrac{h'}{h}\\\\h=\dfrac{10}{1}\\\\h=10\ cm$

So, the size off the object is same as that of the size of the image i.e. 10 cm.

3 0

3 years ago

Part A

Alona [7]

Newton thinks that object falls due to gravity whereas Einstein thinks gravity is not the reason behind it.

<h3>How did Einstein’s and Newton’s theories differ in terms of explaining the cause of gravity?</h3>

Newton concluded that objects fall because they are pulled by Earth's gravity. Einstein's thinks that these objects do not fall due to gravity. According to Einstein, these objects and Earth just freely move in a curved spacetime

So we can conclude that Newton thinks that object falls due to gravity whereas Einstein thinks gravity is not the reason behind it.

Learn more about gravity here: brainly.com/question/940770

#SPJ1

7 0

2 years ago

A charged cork ball is suspended on a light string in the presence of a uniform electric field E~ = (2.2 × 105 N/C)ˆı + (3.6 × 1

MariettaO [177]

Complete Question:

A charged cork ball is suspended on a light string in the presence of a uniform electric field E~ = (2.2 × 105 N/C) i + (3.6 × 105 N/C) j . The ball is in equilibrium in the field. Find the charge on the ball. The acceleration due to gravity is 9.8 m/s 2. The mass of the ball is 0.7g. The length of the string is 1.4m and at an angle of 37 degrees from the center. Answer in units of nC.

Answer:

The charge on the ball is 0.1052 nC

Explanation:

Given;

vertical component of the Electric field, Ey = (3.6 × 10⁵ N/C)

horizontal component of the Electric field, Ex = (2.2 × 10⁵ N/C)

If the cork ball is in equilibrium, then the upward force is equal to the downward force.

Also sum of all the forces acting on the cork ball is zero.

$Tsin \theta = q*E_x -------equation (i)\\\\Tcos \theta+q*E_y-mg= 0-----equation (ii)$

From equation (i)

Tsin(37) = (2.2 × 10⁵)q

$T = \frac{2.2X10^5*q}{sin(37)}--------equation (iii)$

Substitute equation (iii) into equation (ii) and solve for q

$\frac{2.2X10^5*q}{sin(37)}(cos (37)) + q((3.6X 10^5) -(7 X10^{-4} X 9.8) =0\\\\(291949.86)q +(360000)q = 0.00686\\\\(651949.86)q = 0.00686\\\\q = \frac{0.00686}{651949.86} = 1.0522 X 10^{-8} C = 0.1052nC$

Therefore, the charge on the ball is 0.1052 nC

6 0

3 years ago