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Answer: d
Explanation:
Did you actually try to answer the question its obviously d they all have same miles per hour as 100 so there would be nothing different so it would be d.
Answer:
= 128.3 J / kg ° C
Explanation:
In this exercise we will use that the expression for heat is
Q = m ΔT
As they indicate that there are no losses with the medium, the heat transferred by the tungsten is equal to the heat absorbed by the water plus the calorimeter
Q assigned = QAbsorbed
Q hot = Q cold + Q calorimeter
The mass of tungsten (m₁ = 69.12 10⁻³ kg) with an initial temperature (T₁ = 98.93°C),
The mass of water (m₂ = 85.45 10⁻³ kg) at a temperature (T₂ = 23.82°C),
a calorimeter constant (C = 1.56 J/ °C)
m₁ (T₁ - ) = (m₂ + C) ( - T₂)
= (m₂ ce2 + C) (-T₀) / (m₁ (T₁-)
= (85.45 10-3 4186 + 1.56) (25.63 - 23.82) / (69.12 10-3 (98.93 - 25.63))
= (357.69 + 1.56) 1.81 / (69.12 10-3 73.3)
= 650.24 / 5.0665
= 128.3 J / kg ° C
Answer:
The acceleration is
Explanation:
Given that,
Speed
Time t = 60.0 sec
We need to calculate the acceleration
Using formula off acceleration
We know that,
Missile goes from rest
So, Initial velocity =0
Put the value into the formula
On right hand side multiplying and dividing by g = 9.8m/s²
Put the value of g
Hence, The acceleration is
Answer:
a. 25 N/m
b. 0.8886 s
c. 0.707 m/s
d. At the equilibrium point
Explanation:
m = 500 g = 0.5 kg
L = 20 cm = 0.2 m
A = 10 cm = 0.1 m
a. Let g = 10 m/s2, then the gravity of the 0.5 kg book acting on the spring is
F = mg = 0.5*10 = 5 N
If the spring is stretched L = 0.2 m under 5N load, then the spring constant k is:
k = F/l = 5 / 0.2 = 25 N/m
b. We can treat this as simple harmonic motion with magnitude A = 0.1 cm. The period of this motion is
c. The book maximum speed:
d. Due to the law of energy conservation, the maximum speed would occur at the equilibrium point. This is where the potential energy, elastic energy is 0 and the kinetic energy is greatest.