At what temperature would the volume of a gas be 0.550 L if it had a volume of 0.432 L at –20.0 o C?
2 answers:
Answer: 321.6 K
Explanation: Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.
(At constant pressure and number of moles)
where,
= initial volume of gas = 0.432 L
= final volume of gas = 0.550 L
= initial temperature of gas =
= final temperature of gas = ?
Now put all the given values in the above equation, we get the final pressure of gas.
Therefore, the final temperature will be 321.6 K.
You might be interested in
Answer:
1.346 v
Explanation:
1) Fist of all we need to calculate the standard cell potential, one should look up the reduction potentials for the species envolved:
(oxidation) →
E°=0.337 v
(reduction) →
E°=1.679 v
(overall) +8H^{+}_{(aq)}→
E°=1.342 v
2) Nernst Equation
Knowing the standard potential, one calculates the nonstandard potential using the Nernst Equation:
Where 'R' is the molar gas constant, 'T' is the kelvin temperature, 'n' is the number of electrons involved in the reaction and 'F' is the faraday constant.
The problem gives the [red]=0.66M and [ox]=1.69M, just apply to the Nernst Equation to give
E=1.346