1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
devlian [24]
2 years ago
11

To find the atomic mass of a particular atom you need to know

Chemistry
1 answer:
AveGali [126]2 years ago
6 0
The answer is (C) as the definitions states that atomic mass is the number of protons and neutrons.
Hope this helps :).
You might be interested in
calculate the mols of alt gas if the volume is 0.97 liters at a temperature of 12 C and the pressure is 152 Kpa’s
katrin2010 [14]

Answer:

0.062mol

Explanation:

Using ideal gas law as follows;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821Latm/molK)

T = temperature (K)

Based on the information provided;

P = 152 Kpa = 152/101 = 1.50atm

V = 0.97L

n = ?

T = 12°C = 12 + 273 = 285K

Using PV = nRT

n = PV/RT

n = (1.5 × 0.97) ÷ (0.0821 × 285)

n = 1.455 ÷ 23.39

n = 0.062mol

4 0
2 years ago
Describe the basic particle from which all ements are made
maxonik [38]
The answer for this question is: Atoms
7 0
2 years ago
Read 2 more answers
A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical
Katarina [22]

Answer:

empirical formula: H_2SO_4

2 g H

32.7 g S

65.3 g O

Explanation:

Like the problem said, the first thing we can do is calculate the mass of each of the 3 elements in a 100-gram sample:

- 2.00% * 100g = 2 g H

- 32.7% * 100g = 32.7 g S

- 65.3% * 100g = 65.3 g O

Now we need to find the empirical formula from these. To do so, convert all of those masses into moles by using the molar mass for each element:

- the molar mass of H is 1.01 g/mol

- the molar mass of S is 32.06 g/mol

- the molar mass of O is 16 g/mol

2 g H ÷ 1.01 g/mol = 1.98 mol H

32.7 g S ÷ 32.06 g/mol = 1.02 mol S

65.3 g O ÷ 16 g/mol = 4.08 mol O

Our ratio of H : S : O is now:

1.98 mol : 1.02 mol : 4.08 mol

Divide them all by the smallest number, which is 1.02:

1.98/1.02  :  1.02/1.02  :  4.08/1.02

1.94 : 1 : 4

1.94 ≈ 2

So:

2 : 1 : 4

Thus, the empirical formula is: H_2SO_4.

7 0
3 years ago
Which of these best explains the formation of deep ocean currents
timurjin [86]

Answer:

if you could copy and paste the text or a picture of the options, i'd be more than happy to answer

Explanation:

:)

5 0
2 years ago
Why can water pass through sandstrone but not through shale
Valentin [98]
It really depends on the 'type' of rock it is. By this I mean whether it's impermeable or permeable. Impermeable rocks don't allow water through and permeable rocks do. It has to do with how 'porous' a rock is: how many openings it has and how spaced apart are its particles are. Sandstone is permeable and Shale impermeable.
3 0
3 years ago
Other questions:
  • Hydrogen bonds are approximately _____% of the bond strength of covalent c-c or c-h bonds.
    7·1 answer
  • Which class of organic compounds contains nitrogen?
    15·1 answer
  • Give the net ionic equation for the reaction (if any) that occurs when aqueous solutions of Al(C2H3O2)3 and LiNO3 are mixed. Giv
    12·2 answers
  • In a chemical reaction, an iron atom became the ion Fe2+. What happened to the iron atom?
    12·2 answers
  • WILL GIVE BRAINLEST PLZZZ HELP DUE IN 20 MINS ANSWER IF U CAN HELP BTW THERES A Q JUST LIKE THIS ONE ITS IN MY PROFILE IT GIVES
    6·1 answer
  • How many atoms are in 2.00 moles of titanium
    6·1 answer
  • The ester of honey and the test ​
    13·1 answer
  • What is haber's process?​
    10·2 answers
  • HELP ME PLEASE ASAP IVE POSTED THIS LIKE FIVE TIMES AND NO ONES RESPONDED PLEASE!!!!!!!!!!
    9·2 answers
  • Charlie is frying an egg in a pan located over a gas burner. He develops a model to determine the energy produced by the flame i
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!