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marta [7]
2 years ago
15

The chemical equation is Mg(s) + O2(g) → MgO(s)

Chemistry
1 answer:
vredina [299]2 years ago
4 0

Answer:

The magnesium will burn until consumed entirely. There is much more oxygen available in the atmosphere than needed to consume the magnesium. Thus the magnesium is the limiting reactant because it determines the amount of product formed.

Explanation:

Mg produces less amount of MgO than O2; therefore Mg is the limiting reagent. O2 produces more amount of MgO than Mg; therefore O2 is the excess reagent.

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Example/Explanation:

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Explanation:

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What is the temperature of 4.5 moles of a gas that occupies 50. mL at 1.35 atm?
devlian [24]

Answer:

T = 0.182 Kelvin

Explanation:

As we know that

PV = nRT\\

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7 0
3 years ago
The equilibrium constant for the chemical equation is Kp = 5.23 at 191 °C. Calculate the value of the Kc for the reaction at 191
Lapatulllka [165]
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Kp= Kc (RT)^Δn------------------> Kc= Kp/[(RT)^Δn]
 Kp= 5.23
R= 0.0821
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Δn= ?

Kc= 5.23/ (0.0821 x 464)^Δn= ???

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3 years ago
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Answer:

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Explanation:

6 0
3 years ago
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